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Answer:
120 mph
Explanation:
Given:
Δx = 0.25 mi
v₀ = 0 mi/s
t = 15 s
Find: v
Δx = ½ (v + v₀) t
0.25 mi = ½ (v + 0 mi/s) (15 s)
v = 0.0333 mi/s
v = 120 mi/h
Answer:
<h2>a</h2><h2> move with an increasing velocity</h2>
Answer:
(a) W = 8.66 J
(b) Velocity = 2.40 m/s
Explanation:
(a) Work done is given as the product of force and displacement. That is:
W = F * d * cos(A)
Where F = force applied
d = distance moved
A = angle of ramp
Therefore, work done is:
W = 20 * 0.5 * cos30
W = 8.66 J
(b) Work done is equal to change in Kinetic energy. Since the initial kinetic energy is zero:
W = KE(final)
W = ½ * m * v²
Where v = final velocity
=> 8.66 = ½ * 3 * v²
v² = 5.773
v² = 2.40 m/s
Answer:
W = 3.4x0³ J.
Explanation:
The work done by the man is given by the following equation:
(1)
<em>where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.</em>
We need to find first the total force Ft, which is:
<em>where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°. </em>
Hence, the work is:
Therefore, the work done by the man is 3.4x10³ J.
I hope it helps you!
