you have two solid substances that look the same. What measurements would you take and which tests would you preform to determin
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This question involves the concepts of projectile motion and launch speed.
(a) The initial launch speed of the projectile is "100 m/s".
(b) The launch angle of the projectile is "53.13°".
<h3>(a) LAUNCH SPEED</h3>A projectile motion is a motion that takes place on both x and y axes, simultaneously. In this motion the initial launch speed is given by the following formula:
where,
= initial launch speed = ?
= horizontal component of initial launch speed = 60 m/s
= vertical component of initial launch speed = 80 m/s
Therefore,
Launch angle is given by th following formula:
Learn more about the projectile motion here:
Answer:
B = - 1.51 10⁻⁷ T
Explanation:
For this exercise we can use Faraday's law of induction
E = -
In this case, they indicate that the normal and the magnetite field are in the same direction, so the angle is zero (cos 0 = 1), they give the area of the loop A = 4.32 10⁻⁴ m² and since we have N = 1470 turns in each one a voltage is induced
E = - N B A
B = -E A / N (1)
we find the induced voltage with ohm's law
V = i R
where the current is defined by
i = Q / t
we substitute
V = Q R / t
let's calculate
V = 9.18 10-3 56.0 / t
We must assume a time normally is t = 1 s
V = 0.514 V
this is the voltage in the circuit which must be the induced voltage V = E
we substitute in 1
B = - 0.514 4.32 10⁻⁴ / 1470
B = - 1.51 10⁻⁷ T