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Iteru [2.4K]
4 years ago
10

A centimeter is Viooth of a meter, while a kilo-

Engineering
1 answer:
tatuchka [14]4 years ago
8 0

Answer:

b. False

Explanation:

A centimeter is a hundredth of a meter. This means 1/100 ,1 cm = 0.01 m

A kilo is 1000 grams.

The first answer is false because a hundredth isnot written well.

The second statement is false because the comparison given is of different units of measure. For distance is meters where as for weight is kilograms.

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An insulated rigid tank is initially evacuated. A valve is opened, and atmospheric air at 95 kPa and 17 ºC enters the tank until
Darya [45]

Answer:

T2= 406k

Explanation:

The temperature can be defined as the measurement of the intensity of the heat present in the object. Fahrenheit, kelvin and centigrade are the common scale used for measuring Temperature.

Given:

T1=170C

To convert to Kelvin

= 17+273 =290K

T1 = 290K

Pressure (P)= 95KPa

Specific heat ratio = CP/CV= K

WhereK=1.005/0.718

K = 1.4

The final temperature can be calculated using the formula below.

T2 = CP/CV × T1

=. K × T1

T2 = 1.4 × 290

T2= 406k

5 0
3 years ago
Consider a drug-eluting balloon catheter deployed into a blood vessel. The balloon is inflated to perfectly adhere to the vessel
GaryK [48]

Answer:

a)  Cr = Co - Fx / D

b)   ΔC / Δx = ( CR - Cr )  / ( xR - xRo )

Explanation:

A) Derive an expression for the profile c(r) inside the tissue

F = DΔC / X  = D ( Co - Cr ) / X   ------ 1

where : F = flux , D = drug diffusion coefficient

            X = radial distance between Ro and R

Hence : Cr = Co - Fx / D

B) Express the diffusive flux at outer surface of the balloon

Diffusive flux at outer surface =  ΔC / Δx = CR - Cr / xR - xRo

6 0
3 years ago
Who is responsible for keeping your facility in compliance <br>​
inessss [21]
<h2>Answer:</h2><h2>The safety manager is usually the person responsible for ensuring whether the company is in compliance with the OSHA employer requirements . These type of requirements include; Fatal accidents that result in the hospitalisation of three or more employees,must be reported to the OSHA nearest office within 8 hours.</h2>

4 0
3 years ago
One who waits too long to complain has indicated satisfaction with the agreement despite the initial lack of true consent is the
katovenus [111]

Answer: Doctrine of ratification

Explanation:Doctrine of ratification tries to show that a person who is taking so much a time to complain has indicated that he agrees even if he doesn't without a written consent. This is to eliminate undue waste of time in business, legal an other proceedings requiring consent of both parties.

Doctrine of ratification can either be implied or expressed

Implied ratification is the type of ratification where a persons actions or body language can be seen that he has accepted.

Express ratification is a ratification where a person intentionally accept by showing either through written or verbally.

7 0
3 years ago
An automobile travels along a straight road at 15.65 m/s through a 11.18 m/s speed zone. A police car observed the automobile. A
irina [24]

An automobile travels along a straight road at 15.65 m/s through a 11.18 m/s speed zone. A police car observed the automobile. At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile at a constant acceleration of 1.96 m/s2 . The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s2

Find the total time required for the police car  to over take the automobile.

Answer:

15.02 sec

Explanation:

The total time required for the police car to overtake the automobile is related to the distance covered by both  cars which is equal from instant point of abreast.

So; we can say :

D_{pursuit} =D_{police}

By using the second equation of motion to find the distance S;

S= ut + \dfrac{1}{2}at^2

D_{pursuit} = (15.65 *12 )+(15.65 (t)+ (\dfrac{1}{2}*(-3.05)t^2)

D_{pursuit} = (187.8)+(15.65 \ t)-0.5*(3.05)t^2)

D_{pursuit} = (187.8+15.65 \ t-1.525 t^2)

D_{police} = ut _P + \dfrac{1}{2}at_p^2

where ;

u  = 0

D_{police} =  \dfrac{1}{2}at_p^2

D_{police} =  \dfrac{1}{2}*(1.96)*(t+12)^2

D_{police} = 0.98*(t+12)^2

D_{police} = 0.98*(t^2 + 144 + 24t)

D_{police} = 0.98t^2 + 141.12 + 23.52t

Recall that:

D_{pursuit} =D_{police}

(187.8+15.65 \ t-1.525 t^2)=  0.98t^2 + 141.12 + 23.52t

(187.8 - 141.12)  + (15.65 \ t  -  23.52t)  -( 1.525 t^2    - 0.98t^2)  =   0

= 46.68 - 7.85 t -2.505 t² = 0

Solving by using quadratic equation;

t = -6.16 OR  t = 3.02

Since we can only take consideration of the value with a  positive integer only; then t = 3.02 secs

From the question; The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit;

Therefore ; the total time  required for the police car  to over take the automobile = 12 s + 3.02 s

Total time  required for the police car  to over take the automobile = 15.02 sec

8 0
3 years ago
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