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gayaneshka [121]
4 years ago
8

The statement that is NOT true about the difference between laminar and turbulent boundary layers is:1.the Reynolds number for a

turbulent boundary layer is higher than that for a laminar boundary layer. 2.the wall shear stress for a turbulent boundary layer is greater than that for a laminar boundary layer. 3.a turbulent boundary layer is thicker than a laminar boundary layer.4.the velocity gradient at the wall is greater for a laminar boundary layer than a turbulent boundary layer.
Engineering
1 answer:
IgorLugansk [536]4 years ago
6 0

Answer:

4. The velocity gradient at the wall is greater for a laminar boundary layer than a turbulent boundary layer.

Explanation:

This is false

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An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Giv
Anika [276]

The question is incomplete. The complete question is --

An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Given the rod has a diameter of 1.01 cm and the young's modulus of aluminum is 69 GPa, determine the following :

1. the interference value, i

2. the radial pressure at the interference of the collar and the rod

3. the maximum effective stress in the collar

4. if the yield strength of aluminium is 200 MPa and assume a safety factor of 1.5, will the aluminium collar break

Solution:

Given :

Inner radius of the collar = 1 cm

So, inner diameter, $d_1$ = 2 cm

Outer radius of the collar = 12 cm

So, outer diameter, $d_2$ = 4 cm

The aluminium rod diameter, d = 1.01 cm

Now, from the figure, we can see that there will be no interference and so the rod will easily insert inside the collar.

1. So, the interference , i =0

2. The radial pressure is also 0.

3. There will be no stress developed. So the maximum effective stress is 0

4. The collar will not break

8 0
3 years ago
2 Describe the four major disciplines of engineering and identify problems or projects that an engineer in each discipline might
Harman [31]
Answer: Starting of with Chemical Engineering something that they may encounter is a lack of adeptness man puissance. People that are working there are not much adept or having cognizance regarding to chemical industry. Something someone with a Civil engineering might encounter is the quandary of sustainable construction, and amendment construction site safety. To go on , something that Electrical engineering might encounter is a Non technical , Virtually an electrical engineer has to deal with an astronomical range of machines , control panels,instruments. For example you are working with circuit breakers,as anon as you’ll have expertise on any particular type of circuit breaker, there's a transmutation in trend and the CB you are working with is already obsolete. And last but no least , Something someone might encounter while doing Mechanical engineering is there toxic substances because their work environment is susceptible to fires, explosions, structural failures and equipment malfunctions.
5 0
3 years ago
Please answer fast. With full step by step solution.​
lina2011 [118]

Let <em>f(z)</em> = (4<em>z </em>² + 2<em>z</em>) / (2<em>z </em>² - 3<em>z</em> + 1).

First, carry out the division:

<em>f(z)</em> = 2 + (8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1)

Observe that

2<em>z </em>² - 3<em>z</em> + 1 = (2<em>z</em> - 1) (<em>z</em> - 1)

so you can separate the rational part of <em>f(z)</em> into partial fractions. We have

(8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1) = <em>a</em> / (2<em>z</em> - 1) + <em>b</em> / (<em>z</em> - 1)

8<em>z</em> - 2 = <em>a</em> (<em>z</em> - 1) + <em>b</em> (2<em>z</em> - 1)

8<em>z</em> - 2 = (<em>a</em> + 2<em>b</em>) <em>z</em> - (<em>a</em> + <em>b</em>)

so that <em>a</em> + 2<em>b</em> = 8 and <em>a</em> + <em>b</em> = 2, yielding <em>a</em> = -4 and <em>b</em> = 6.

So we have

<em>f(z)</em> = 2 - 4 / (2<em>z</em> - 1) + 6 / (<em>z</em> - 1)

or

<em>f(z)</em> = 2 - (2/<em>z</em>) (1 / (1 - 1/(2<em>z</em>))) + (6/<em>z</em>) (1 / (1 - 1/<em>z</em>))

Recall that for |<em>z</em>| < 1, we have

\displaystyle\frac1{1-z}=\sum_{n=0}^\infty z^n

Replace <em>z</em> with 1/<em>z</em> to get

\displaystyle\frac1{1-\frac1z}=\sum_{n=0}^\infty z^{-n}

so that by substitution, we can write

\displaystyle f(z) = 2 - \frac2z \sum_{n=0}^\infty (2z)^{-n} + \frac6z \sum_{n=0}^\infty z^{-n}

Now condense <em>f(z)</em> into one series:

\displaystyle f(z) = 2 - \sum_{n=0}^\infty 2^{-n+1} z^{-(n+1)} + 6 \sum_{n=0}^\infty z^{-n-1}

\displaystyle f(z) = 2 - \sum_{n=0}^\infty \left(6+2^{-n+1}\right) z^{-(n+1)}

\displaystyle f(z) = 2 - \sum_{n=1}^\infty \left(6+2^{-(n-1)+1}\right) z^{-n}

\displaystyle f(z) = 2 - \sum_{n=1}^\infty \left(6+2^{2-n}\right) z^{-n}

So, the inverse <em>Z</em> transform of <em>f(z)</em> is \boxed{6+2^{2-n}}.

4 0
3 years ago
You are given a collection of n bottles of different widths and n lids of different widths and you need to find which lid goes w
Sladkaya [172]

Answer:

void bubble_sort( int A[ ], int n ) {

     int temp;

     for(int k = 0; k< n-1; k++) {

          // (n-k-1) to ignore comparisons of already compared iterations

         for(int i = 0; i < n-k-1; i++) {

                 if(A[ i ] > A[ i+1] ) {

                      // swapping occurs here

                      temp = A[ i ];

                      A[ i ] = A[ i+1 ];

                      A[ i + 1] = temp ;

                  }

          }

    }

}

5 0
3 years ago
How nany degrées is the included angle of General Purpose Acme threads? A. 60 B. 29 c. 14.5 D. 10
horrorfan [7]

Answer:

B.29

Explanation:

In general purpose acme thread:

  Nominal depth of thread=0.5ltimes Pitch

  Included angle =29 degrees

Generally Acme thread are following types

  1.General purpose(G) Acme

  2.Centralizing(C) Acme

  3. Stub Acme  

Centralizing(C) Acme threads have tighter tolerance during manufacturing as compare to General purpose(G) Acme  threads.

8 0
3 years ago
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