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Firdavs [7]
3 years ago
6

“Gasoline boils at a relatively low temperature (about 150°C). The kerosene is removed at around 200°C, followed by diesel oil a

t 300°C and fuel oil at around 370°C.”
Chemistry
2 answers:
Serga [27]3 years ago
7 0

Answer: distillation

Explanation:

jekas [21]3 years ago
4 0
The correct answer is letter a. distillation of a mixture. “Gasoline boils at a relatively low temperature (about 150°C). The kerosene is removed at around 200°C, followed by diesel oil at 300°C and fuel oil ataround 370°C," It is the process of DISTILLATION OF A MIXTURE.Here is the question.
<span>
What topic is the teacher most likely talking about?
a. distillation of a mixture
b. filtration of a pure substance
c.evaporation of a mixture
d. sorting of a pure substance</span>
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A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) &lt;---&gt; N2(g) 3H2(g) At equilibrium, it was fou
Softa [21]

Answer:

Kc for this equilibrium is 2.30*10⁻⁶

Explanation:

Equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction and the concentrations of reactants and products are held constant.

Being:

aA + bB ⇔ cC + dD

the equilibrium constant Kc is defined as:

Kc=\frac{[C]^{c}*[D]^{d}  }{[A]^{a} *[B]^{b} }

In other words, the constant Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients. Kc is constant for a given temperature, that is to say that as the reaction temperature varies, its value varies.

In this case, being:

2 NH₃(g) ⇔ N₂(g) + 3 H₂(g)

the equilibrium constant Kc is:

Kc=\frac{[N_{2} ]*[H_{2} ]^{3}  }{[NH_{3} ]^{2} }

Being:

  • [N₂]= 0.0551 M
  • [H₂]= 0.0183 M
  • [NH₃]= 0.383 M

and replacing:

Kc=\frac{0.0551*0.0183^{3}  }{0.383^{2} }

you get:

Kc= 2.30*10⁻⁶

<u><em>Kc for this equilibrium is 2.30*10⁻⁶</em></u>

8 0
3 years ago
What is true when an element is oxidized? It bonds with the hydroxide ion. It loses electrons to another element. It reacts with
Mama L [17]

Answer: It loses electrons to another element.

Explanation:- Oxidation is the process in which an element loses electrons and there is an increase in the oxidation state. On losing electrons it combines with a electronegative element such as oxygen, sulphur or nitrogen etc.

Fe\rightarrow Fe^{2+}+2e^-

Reduction is the process in which an element gains electrons and there is a decrease in the oxidation state.

\frac{1}{2}O_2+2e^-\rightarrow O^{2-}

8 0
3 years ago
Five students performed a Kjeldahl nitrogen analysis of a protein sample. The following weight % nitrogen values were determined
Sunny_sXe [5.5K]

Answer:

G_calculated = 1.756

The outlier should be rejected, as G_cal > G_tab (= 1.463) at 95 % confidence.

Explanation:

The Grubb's test is used for identifying an outlier in data, which is from the same population. For this, a statistical term, G, is calculated for the suspected outlier. If the calculated value is greater than the tabulated G value then the suspected value is rejected. This term is given as,

G_calculated = | suspect value - mean| / s

Here,  suspect value is 13.8, mean is to be taken of all the data (including suspected value). s is the standard deviation of the sample data.

s is calculated from the following formula:

s = (Σ(xi - x)²/(N-1))^1/2

Here, x is the mean, which is 15.24, xi is individual value and N is the total number of data (5).

From the above formula, s is found to be

Standard Deviation, s = 0.820

Now for G value,

G_calculated = | 13.8 - 15.24| / (0.820)

G_ calculated = 1.756

The tabulated G value at 95 % confidence and N -1 (5 - 1 = 4) degree of freedom is, 1.463.

As calculated G (1.756) is greater than the tabulated G (1.463), the value 13.8 is considered an outlier at 95 % confidence.  

3 0
3 years ago
Explain why lithium is a strong reducing agent, whereas fluorine is a strong oxidizing agent.
Tom [10]
Lithium is a good reducing agent because it is electropositive [it rapidly gains electrons]
fluorine is  good oxidizing agent electronegative [it loses electrons fastly]
3 0
3 years ago
True or False. If a fire destroyed all of the grass in a grassland, this would NOT affect the biodiversity of this ecosystem.
Andrews [41]

Answer:

This is false

5 0
3 years ago
Read 2 more answers
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