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nydimaria [60]
2 years ago
12

Use the table to determine the number of protons for each atom. Then, choose the statement below that is true about the two atom

s.
O Atoms X and Atom Y are in the same family.
O Atom X is in a column to the right of Atom Y on the periodic table.
O Atom X and Atom Y are in the same row on the periodic table.
O Atoms X and Atom Y are isotopes.

Chemistry
1 answer:
Lilit [14]2 years ago
5 0
C
The elements are Lithium and Beryllium— just look at the mass number on the periodic table
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In the molecule ClF3, chlorine makes three covalent bonds. Therefore, three of its seven valence electrons need to be unpaired.
Kisachek [45]

Answer:

Explanation:

Chlorine has electronic configuration of 2 , 8 , 7

In n = 3 there are 7 electrons out of which 2 are in s , and 5 are in p . But out of 5 electrons in p , one electron jumps into d orbital . so the electronic configuration  becomes as follows

3s^23p_x^23p_y^23p_z^1  = 7

3s^23p_x^23p_y^13p_z^13d_{xy}^1

These orbitals like sp³d hybridise to form 7 degenerate orbitals out of which 2 orbitals contain electrons in pairs and rest three are singly occupied by electrons.( unpaired electrons )

3 0
3 years ago
Hi ! Could someone help me out with this last part to my chemistry practice ? Thank you !
skelet666 [1.2K]

After 100years, sample is 250g

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7 0
3 years ago
What is the formula for finding the density of<br> an object?
TEA [102]
The answer would be:
D = M/V

D=Density
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3 0
3 years ago
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What factor is responsible for keeping the inner core in a solid state
Mrrafil [7]
High pressure and heat
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3 years ago
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Current is applied to a molten mixture of AgF , FeCl2 , and AlBr3 . What is produced at each electrode? STRATEGY Rank the cation
ratelena [41]

Answer:

Cathode: Ag

Anode: Br₂

Explanation:

In the cathode must occur a reduction, so it's more likely to a metal atom be in the cathode. For the metals given the reduction reactions and the potential of reduction are:

Ag⁺ + e⁻ ⇒ Ag⁰ E° = + 0.80 V

Fe⁺² + 2e⁻ ⇒ Fe⁰ E° = - 0.44 V

Al⁺³ + 3e⁻ ⇒ Al⁰ E° = -1.66 V

As the potential for Ag is the higher, the reduction will occur for it first, so in the cathode will produce Ag.

For the anode an oxidation must occurs, so the reactions for the nonmetals are:

F₂ + 2e⁻ ⇒ 2F⁻ E° = +2.87 V

Cl₂ + 2e⁻ ⇒ 2Cl⁻ E° = +1.36 V

Br₂ + 2e⁻ ⇒ 2Br⁻ E° = +1.07 V

For oxidation, the less the E°, the faster the reaction will occur, so Br₂ will be formed in the anode.

5 0
3 years ago
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