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pav-90 [236]
2 years ago
7

Endler's Guppies Experiment on Natural Selection

Chemistry
1 answer:
Morgarella [4.7K]2 years ago
7 0

In conclusion, an experiment about Natural Selection includes mechanisms, explanation, estimation of the frequency of the trait and comparisons.

<h3>What is the scientific method?</h3>

The scientific method is a series of step used to validate evidence and thus formulate theories.

Darwin used the scientific method to draw conclusions about the main mechanism of evolution, i.e., natural selection.

The scientific method involves making a question, providing an explanation of the hypothesis, making observations/experiments (which include experimental and control groups), and drawing conclusions.

The empirical data serve to test a hypothesis (either confirm or reject it) by contrasting its results with predictive outcomes.

The strength of the conclusions can be enhanced by using supporting evidence from other research fields (in this case, for example, the fossil record).

In conclusion, an experiment on Natural Selection includes mechanisms (question), explanation (hypothesis), estimation of the frequency of the trait in the population (prediction) and comparisons (control group).

Learn more about the scientific method here:

brainly.com/question/17216882

#SPJ1

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Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


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