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pantera1 [17]
3 years ago
6

During steps 2-5, the

Chemistry
2 answers:
JulsSmile [24]3 years ago
7 0

Answer: temperature, reaction rate and constant:)

crimeas [40]3 years ago
4 0

Answer:

Temperature was independent

Reaction rate is dependent

Other factors are constant

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James decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jame
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One mile every 15 minutes
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3 years ago
Calculate the food energy (joules/
Anna007 [38]

Calculate the food energy (joules/g) of one of your food samples. one chemistry calorie is equal to 4.186 joules. convert the energy you calculated to kilojoules (1 kj = 1000 j). since nothing is given, an example is avocadoes have 160 cal/100 g serving

(160 cal/ 100 g)(4.186 J/ 1 cal) (1 kJ/1000 J) = 0.0067 kJ/g

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Prove how the Law Conservation of Mass and Enery apply to Cellular Respiration​
snow_lady [41]

Answer:

mass and energy is reused when those things happen

7 0
3 years ago
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
What is the molarity of a solution containing 56 grams of solute in 959 ml of solution? (molar mass of solute = 26 g/mol)?
jolli1 [7]
26g --- 1 mol
56g --- X
X= 56/26 = 2,154 mol

959 ml = 959cm³ = 0,959dm³

C = n/V
C = 2,154/0,959
C = 2,246 mol/dm³
8 0
3 years ago
Read 2 more answers
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