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Gnoma [55]
3 years ago
11

Why are both accuracy and precision important in making a measurement

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
4 0
It is because precise amount measured is required for the reaction to take place chemically, and an accurate conclusion will prevent any dangerous and misleading conclusions made due to inaccurate data.

For example, in physics, every measurement we state the instrument uncertainty after the measurement, stating that it is not a definite certain measurement, but the smaller the value for the uncertainty, the more precise that instrument's data is.

Precise is important in terms of knowing how many moles or grams of reactant is required for this reaction to complete without any shortage or excess chemically. Accuracy is based on the conclusions we make in regards to the data and observations we make experimentally.
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Chemistry! help! Please!
VMariaS [17]

Answer:

2. a. All three solutes are nonelectrolytes.

3. a. the solution of solute X

Explanation:

The freezing point depression (ΔTf) and <em>boiling point elevation</em> (ΔTb) are <em>colligative properties</em>: they depend on the <em>numbers of particles</em>.

The formula for ΔTf is

ΔTf = iKf·b

i is the van’t Hoff factor: the number of moles of particles you get from a solute.

For sucrose,

Sucrose (s) ⟶ sucrose (aq)

1 mole sucrose ⟶ 1 mol particles         i = 1

For NaCl

NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)

1 mol           1 mol     +   1 mol                 i = 2

For Ca(NO₃)₂

Ca(NO₃)₂(s) ⟶ Ca²⁺(aq) + 2NO₃⁻(aq)

1 mol                     1 mol       +  2 mol     i = 3

===============

2. <em>Freezing points </em>

For a nonelectrolyte, i = 1.

Kf = 1.86 °C·kg⁻¹mol⁻¹

b = 1 mol/kg          Calculate ΔTf

ΔTf = 1 × 1.86 × 1

ΔTf = 1.86 °C

Tf = Tf⁰ - ΔTf =0.00 °C – 1.86 °C = -1.86 °C

All the other solutions have lower freezing points, so the solutes must be <em>electrolytes</em>.

===============

3. <em>Boiling points</em>

The formula for ΔTb is

ΔTb = iKb·m

The solution with the <em>highest boiling point</em> will have the <em>highest value of i. </em>

In other words, the solution with the highest boiling point will be the one with the <em>lowest freezing point</em>.

That’s the solution of solute X.

5 0
3 years ago
Suppose you carry out a titration involving 3.00 molar HCl and an unknown concentration of KOH. To bring the reaction to its end
snow_tiger [21]

Answer: The concentration of the KOH solution is 1.01 M

Explanation:

According to neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of HCl = 1

n_2 = acidity of KOH = 1

M_1 = concentration of HCl = 3.00 M

M_2 = concentration of KOH = ?

V_1 = volume of HCl = 35.3 ml

V_2 = volume of KOH = 105.0 ml

Putting the values we get:

1\times 3.00\times 35.3=1\times M_2\times 105.0

M_2=1.01

Thus the concentration of the KOH solution is 1.01 M

3 0
4 years ago
Irma has $500 to open a checking account. She wants an account with the lowest fees. She plans to use only her bank's ATM to
Archy [21]

the answer is account A

8 0
3 years ago
Read 2 more answers
Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
zaharov [31]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

  • V = 2.4 L = 0.0024
  • P = 86126.25 Pa
  • T =  287 K
  • m = 0.622
  • R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass =  7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

brainly.com/question/4147359

#SPJ1

4 0
2 years ago
What is Radio Waves and its defonation
Gala2k [10]

Answer:

radio waves are the sound waves that are produces by a radio

Explanation:

6 0
3 years ago
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