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marissa [1.9K]
3 years ago
14

A hockey puck is given an initial speed of 5.0 m/s. If the coefficient of kinetic friction between the puck and the ice is 0.05,

how far does the puck slide before coming to rest? Solve this problem using conservation of energy.
Physics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

d = 25.51 m

Explanation:

the law of the conservation of energy says that:

E_i - E_f = W_f

where E_i is the inicial energy, E_f is the final energy and W_f is the work of the friction.

so:

E_i = \frac{1}{2} MV^2

E_f = 0

where M is the mass and V the velocity.

also,

W_f = U_kNd

where U_k is the coefficient of kinetic frictio, N is the normal force and d is the distance.

therefore:

\frac{1}{2}MV^2=U_kNd

also, N is equal to the mass of the hockey puck multiplicated by the gravity.

replacing:

\frac{1}{2}m(5)^2=(0.05)(m(9.8))(d)

canceling the m:

\frac{1}{2}5^2=0.05(9.8)(d)

solving for d:

d = \frac{\frac{1}{2}5^2 }{0.05(9.8)}

d = 25.51 m

 

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