To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:
Where,
B= Magnetic Field
l = length
= Vacuum permeability
= Vacuum permittivity
Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to
Recall that the speed of light is equivalent to
Then replacing,
Our values are given as
Replacing we have,
Therefore the magnetic field around this circular area is
Answer:
The maximum amplitude (
) will be 7.96 V.
Explanation:
We know, for distortion free operation, the slew rate (S) of an OPAMP is written as
where '
' is the highest frequency signal.
Therefore, from the above equation we can write,
If it produces 20J of light energy in a second, then that 20J is the 10% of the supply that becomes useful output.
20 J/s = 10% of Supply
20 J/s = (0.1) x (Supply)
Divide each side by 0.1:
Supply = (20 J/s) / (0.1)
<em>Supply = 200 J/s </em>(200 watts)
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Here's something to think about: What could you do to make the lamp more efficient ? Answer: Use it for a heater !
If you use it for a heater, then the HEAT is the 'useful' part, and the light is the part that you really don't care about. Suddenly ... bada-boom ... the lamp is 90% efficient !
Answer:
a) 
, b) 
Explanation:
a) The magnetic force experimented by a particle has the following vectorial form:
The charge of the electron is equal to 
. Then, cross product can be solved by using determinants:
The magnetic force is:
b) The charge of the proton is equal to 
. Then, cross product has the following determinant:
The magnetic force is:
Hi!
<span>Acceleration is the rate of change of</span> velocity
Velocity is the rate of speed of an object
