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Evgen [1.6K]
3 years ago
13

A lever has an input arm 50 centimeters long and an output arm 40 centimeters long. What is the mechanical advantage of the leve

r? (MA=Input distance / Output distance) a 2.0 b 1.25 c 1 d 0.8
Physics
2 answers:
taurus [48]3 years ago
4 0

Answer:

45

Explanation:

well 45

Fofino [41]3 years ago
3 0
45 I think is the Anwser
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A stone on ground is zero energy​
NNADVOKAT [17]

Answer:

A stone on the ground does not have zero energy…there is an internal potential in every object. Aldo is not in action or in any mechanical motion it is being acted upon by gravity and also molecular forces and energy.

<em>Hope</em><em> </em><em>this</em><em> helps</em><em> </em><em>!</em>

7 0
3 years ago
A 19kg block is being pulled with a constant horizontal force of 95 Newton’s while also experiencing a constant friction force o
yuradex [85]

Answer:

A

⋅(19kg)=19Akg

95=19Akg

19=19Ak

Explanation:

5 0
3 years ago
A proton moving with a velocity of 4.0 × 104 m/s enters a magnetic field of 0.20 t. if the angle between the velocity of the pro
svlad2 [7]

Answer:

Magnitude of the force on proton = F = 1.1085 × 10^-15 N

Explanation:

Charge on proton = q = 1.60 × 10^-19 C

Velocity of proton = V = 4.0 × 10^4 m/s

Magnetic field = B = 0.20 T  

Angle between V and B = θ = 60

We know that,  

F = qVBsin θ = (1.60 × 10^-19)( 4.0 × 10^4)( 0.20)sin(60)

F = 1.1085 × 10^-15 N    

8 0
3 years ago
Read 2 more answers
Sound travels through a ​
attashe74 [19]

Answer:

A.3.64 m

Explanation:

Because

  • v=(fλ)
  • (1382)=(380)λ
  • λ=3.637m~3.64m

<em>where</em><em> </em><em>,</em><em>v</em><em>=</em><em>velocity</em>

<em>f</em><em>=</em><em>frequency</em><em> </em>

<em>λ</em><em>=</em><em>wave</em><em> </em><em>length</em><em> </em>

8 0
1 year ago
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If a car is taveling with a speed 6 and comes to a curve in a flat road with radius ???? 13.5 m, what is the minumum value the c
Lemur [1.5K]

Answer:

\mu_s \geq 0.27

Explanation:

The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

f_s=\frac{mv^{2}}{R}

But we know that:

f_s\leq \mu_s N

And the normal force is given by the sum of the forces in the vertical direction:

N-mg=0 \implies N=mg

Finally, we have:

f_s=\frac{mv^{2}}{R}  \leq \mu_s mg\\\\\implies \mu_s\geq \frac{v^{2}}{gR}  \\\\\mu_s\geq \frac{(6\frac{m}{s}) ^{2}}{(9.8\frac{m}{s^{2}})(13.5m) }\\\\\mu_s\geq0.27

So, the minimum value for the coefficient of friction is 0.27.

4 0
3 years ago
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