Answer:
B) Polonium and Arsenic
Explanation:
Metalloids are a small category of elements that are right between metals and non-metals, and have properties from those categories.
The most recognized are: Boron, Silicon, Germanium, Arsenic, Antimony, and Tellurium.
Some that are irregularly recognized are Polonium and Astatine.
The only option with the elements in either of the shown elements is B) Polonium and Arsenic.
The amount of a
substance can be converted into grams of that substance by using the molar
mass. It is a physical property of a substance which describes the mass per
mole of the substance. The molar mass of CH3OH is 32.04 g/ mol. Multiplying the
given amount of CH3OH with the molar mass will yield to the mass of the substance.
<span>9.09x10^24 molecules CH3OH ( 1 mol / 6.022x10^23 molecules) (32.04 g/mol) = 483.63 g CH3OH
Dividing the molar mass of N2O which is 44.08 g/mol to the given amount will yield to the number of moles.
0.183 g N2O / 44.08 g/ mol =0.0042 mol N2O</span>
Answer:
The correct option is: A. 0.168 M
Explanation:
Chemical reaction involved:
5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O
Given: <u>For MnO₄⁻ solution</u>-
Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;
<u>For Fe²⁺ solution</u>:
Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M
<u><em>To find out the concentration of Fe²⁺ solution (M₂), we use the equation:</em></u>




<u>Therefore, the concentration or molarity of Fe²⁺ solution: </u><u>M₂ = 0.168 M</u>
Answer: The results of Rutherford's gold foil experiment gave him the evidence to arrive at two conclusions: (1) an atom was much more than just empty space and scattered electrons and (2) an atom consists of a positive charge at the center where most of its mass is placed.
Explanation:
Ernest Rutherford performed an experiment in which he passed alpha particles through a thin gold foil sheet. Through this sheet some of the particles passed on to the other side but some of them were reflected back.
This experiment was done by Rutherford to prove than an atom contains a tiny and heavy nucleus. He concluded that an atom has more than empty space and electrons were present in scattered form.
Also, he concluded that an atom consists of a positive charge at the center where most of its mass is placed.
Thus, we can conclude that the results of Rutherford's gold foil experiment gave him the evidence to arrive at two conclusions: (1) an atom was much more than just empty space and scattered electrons and (2) an atom consists of a positive charge at the center where most of its mass is placed.