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3 years ago

Describe a device that would allow you to measure the acidity of rain. How would that design work, and what would it look like?

Chemistry

1 answer:

riadik2000 [5.3K]3 years ago

4 0

A rain gauge a (clear) tube or cup with inches marked and set outside when raining and see how much rain there is

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Please help thank you

puteri [66]

Answer:

B) Polonium and Arsenic

Explanation:

Metalloids are a small category of elements that are right between metals and non-metals, and have properties from those categories.

The most recognized are: Boron, Silicon, Germanium, Arsenic, Antimony, and Tellurium.

Some that are irregularly recognized are Polonium and Astatine.

The only option with the elements in either of the shown elements is B) Polonium and Arsenic.

6 0

3 years ago

What is the mass (in grams) of 9.09x10^24 molecules of methanol (CH3OH)?

zloy xaker [14]

The amount of a substance can be converted into grams of that substance by using the molar mass. It is a physical property of a substance which describes the mass per mole of the substance. The molar mass of CH3OH is 32.04 g/ mol. Multiplying the given amount of CH3OH with the molar mass will yield to the mass of the substance.

9.09x10^24 molecules CH3OH ( 1 mol / 6.022x10^23 molecules) (32.04 g/mol) = 483.63 g CH3OH

Dividing the molar mass of N2O which is 44.08 g/mol to the given amount will yield to the number of moles.

0.183 g N2O / 44.08 g/ mol =0.0042 mol N2O

8 0

2 years ago

The overall order of an elementary step directly corresponds to its molecularity.

inna [77]

Answer:

true

Explanation:

7 0

3 years ago

Ferris & Mona used the ORP sensor to titrate a ferrous ammonium sulfate solution, (NH4)2Fe(SO4)2 with KMnO4 titrant.

DIA [1.3K]

Answer:

The correct option is: A. 0.168 M

Explanation:

Chemical reaction involved:

5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O

Given: For MnO₄⁻ solution-

Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;

For Fe²⁺ solution:

Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M

To find out the concentration of Fe²⁺ solution (M₂), we use the equation:

$\frac{M_{1}\times V_{1}}{n_{1}} = \frac{M_{2}\times V_{2}}{n_{2}}$

$\frac{0.0250 M\times 20.2 mL}{1} = \frac{M_{2}\times 15 mL}{5}$

$0.505 = M_{2}\times 3$

$M_{2} = \frac{0.505}{3} = 0.168M$

Therefore, the concentration or molarity of Fe²⁺ solution: M₂ = 0.168 M

8 0

3 years ago

The results of Rutherford's gold foil experiment gave him the evidence to arrive at two conclusions: (1) an atom was much more t

Vedmedyk [2.9K]

Answer: The results of Rutherford's gold foil experiment gave him the evidence to arrive at two conclusions: (1) an atom was much more than just empty space and scattered electrons and (2) an atom consists of a positive charge at the center where most of its mass is placed.

Explanation:

Ernest Rutherford performed an experiment in which he passed alpha particles through a thin gold foil sheet. Through this sheet some of the particles passed on to the other side but some of them were reflected back.

This experiment was done by Rutherford to prove than an atom contains a tiny and heavy nucleus. He concluded that an atom has more than empty space and electrons were present in scattered form.

Also, he concluded that an atom consists of a positive charge at the center where most of its mass is placed.

Thus, we can conclude that the results of Rutherford's gold foil experiment gave him the evidence to arrive at two conclusions: (1) an atom was much more than just empty space and scattered electrons and (2) an atom consists of a positive charge at the center where most of its mass is placed.

7 0

3 years ago