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4 years ago

6

which two atoms will form the most polar covalent bond? Electronegativity values for these elements are:O=3.44 C=2.55 N=3.04 H=2

.20

1 answer:

Daniel [21]4 years ago

8 0

Oxygen and hydrogen will form the most polar covalent bond(s) because the difference between their electronegativities is the greatest.

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If you were approaching the solar system in a spaceship, you would notice that the Sun

kozerog [31]

Answer:

No

Explanation:

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4 years ago

if callie has 1,012 beads. and she wants to divide the beads evenly to make 22 necklaces. how many beads will be used for each n

borishaifa [10]

1012/22 = 46

46 beads will be used in each necklace

hope this helps

7 0

4 years ago

Read 2 more answers

Write a paragraph explaining the effect of surface area on the rate of reaction.

nexus9112 [7]

(For a bit of context I will use the reaction between HCl and Mg as an example)

The larger the surface area of the magnesium metal, the more particles are exposed to collide with the aqueous HCl particles to cause the reaction to occur. This increases the frequency per second of collisions, speeding up the rate of reaction.

The effect of a catalyst is to reduce the minimum collision energy which allows the reaction to happen. This does not increase the number of collisions per second, but increases the percentage of successful collisions, which consequently causes the rate of reaction to increase .

I have drawn diagrams showing the effect of surface area, but there isn't really a meaningful diagram that I know of to show the impact of a catalyst (at least not at GCSE level).

6 0

3 years ago

How many liters of 15.0 molar NaOH stock solution will be needed to make 17.5 liters of a 1.4 molar NaOH solution? Show the work

strojnjashka [21]

2.0 L
The key to any dilution calculation is the dilution factor

The dilution factor essentially tells you how concentrated the stock solution was compared with the diluted solution.

In your case, the dilution must take you from a concentrated hydrochloric acid solution of 18.5 M to a diluted solution of 1.5 M, so the dilution factor must be equal to

DF=18.5M1.5M=12.333

So, in order to decrease the concentration of the stock solution by a factor of 12.333, you must increase its volume by a factor of 12.333by adding water.

The volume of the stock solution needed for this dilution will be

DF=VdilutedVstock⇒Vstock=VdilutedDF

Plug in your values to find

Vstock=25.0 L12.333=2.0 L−−−−−

The answer is rounded to two sig figs, the number of significant figures you have for the concentration od the diluted solution.

So, to make 25.0 L of 1.5 M hydrochloric acid solution, take 2.0 L of 18.5 M hydrochloric acid solution and dilute it to a final volume of 25.0 L.

IMPORTANT NOTE! Do not forget that you must always add concentrated acid to water and not the other way around!

In this case, you're working with very concentrated hydrochloric acid, so it would be best to keep the stock solution and the water needed for the dilution in an ice bath before the dilution.

Also, it would be best to perform the dilution in several steps using smaller doses of stock solution. Don't forget to stir as you're adding the acid!

So, to dilute your solution, take several steps to add the concentrated acid solution to enough water to ensure that the final is as close to 25.0 L as possible. If you're still a couple of milliliters short of the target volume, finish the dilution by adding water.

Always remember

Water to concentrated acid →.NO!

Concentrated acid to water →.YES!

8 0

4 years ago

What is the amount in moles 3.40 g Zn

Sidana [21]

<h3>Answer:</h3>

0.0520 mol Zn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.40 g Zn

<u>Step 2: Identify Conversions</u>

Molar Mass of Zn - 65.39 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.40 \ g \ Zn(\frac{1 \ mol \ Zn}{65.39 \ g \ Zn})$
Divide: $\displaystyle 0.051996 \ mol \ Zn$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.051996 mol Zn ≈ 0.0520 mol Zn

3 0

3 years ago