The distance covered will be 0.301m.
firstly we will new to calculate acceleration (a).
we can do so using newtons first law of motion.
v=u + a × t
where
a is the acceleration
t is the time
from here we get
a=(v-u)/t
a=(4-0)/0.15
a=26.67m/s²
using newtons second law of motion
s=u.t+1/2at²
where s is distance travelled in t seconds.
we get,
s=0.301m
learn more about newtons law of motion here:
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Isaac newton, newton’s 2nd law, acceleration, forces, velocity
A real question, one with a question mark?
Answer:
Explanation:
Here the total force at the horizontal components will be equal to the centripetal force on the car. So we will have:
(1)
- f(fr) is the friction force
- N is the normal force
Now, the sum of forces at the vertical direction is equal to 0.
(2)
Let's combine (1) and (2) to find f(fr)
I hope it helps you!
Answer:
A velocity of
Explanation:
Since the magnitude of the vector is equal to the magnitude of velocity, velocity of the 2 cm vector represents a velocity of $10\times 2= 20 \: km/h$.