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Gelneren [198K]

3 years ago

7

The sun's _____ is the layer that emits visible light.

1 answer:

galben [10]3 years ago

7 0

The Photosphere is the right answer

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A 1200 kg car accelerats from reat to 10.0 m/s in a time of 4.50 seconds. Calculate the force that thr car's tires exerted on th

Aleksandr [31]

Answer:

2667 N

Explanation:

<h2>Method 1: Impulse </h2>

We can solve this problem by using the impulse formula.

FΔt = mΔv
Δt = time interval, m = mass of the car (kg), Δv = change in velocity

We have three known variables, so we can solve for the fourth: F.

Divide Δt from both sides to isolate F.

F = (mΔv)/Δt

Substitute known values into the equation.

F = [(1200 kg)(10 m/s - 0 m/s)] / 4.5 s
F = [(1200)(10)]/4.5
F = 12000/4.5
F = 2666.666667 N

The force that the car's tires exert on the road is 2667 N.

<h2>Method 2: Newton's Second Law</h2>

The force that the car's tires exert on the road is equivalent to the force that the road exerts on the car due to Newton's Third Law of Motion.

We can calculate the force that the car's tires exert on the road by using the formula F = ma, which was derived from Newton's Second Law of Motion.

F = ma
F = force exerted on the car, m = mass of the car (kg), a = acceleration of the car (m/s²)

We are given the mass of the car, velocity of the car, and the time in which it accelerated.

We can use this equation for acceleration:

a = Δv/Δt
Δv = final velocity - initial velocity (change in velocity), Δt = time interval

The car started from rest, meaning it had an initial velocity of 0 m/s. Its final velocity was 10 m/s. The time that it took for the car to go from 0 m/s to 10 m/s was 4.5 seconds.

a = (10 m/s - 0 m/s) / 4.50 s
a = 10/4.5
a = 2.222... m/s²

Now we have two known variables, mass and acceleration. We can solve for the force exerted on the car (and thus, the force the car exerts on the road) using the formula F = ma.

F = ma
F = (1200 kg)(2.222... m/s²)
F = 1200 · 2.222...
F = 2666.666667 N

The force that the car's tires exert on the road is 2667 N.

7 0

2 years ago

you throw a rock with a horizontal velocity at 36.6 m/s out a window that is 29.5 m above the ground. What was it’s total time i

ANEK [815]

29.5-4.9x^2= your answer

4 0

3 years ago

Biological dad means

inna [77]

Answer:

Your real dad according to Science and your DNA codes.

7 0

3 years ago

Read 2 more answers

A spring is hanging from the ceiling. When a 250 gram of mass is attached to the free end, the spring elongates by 5 cm. The spr

lord [1]

Answer:

k = 49 N/m

Explanation:

Given that,

Mass, m = 250 g = 0.25 kg

When the mass is attached to the end of the spring, it elongates 5 cm or 0.05 m. We need to find the spring constant. Let it is k.

The force due to mass is balanced by its weight as follows :

mg=kx

$k=\dfrac{mg}{x}\\\\k=\dfrac{0.25\times 9.8}{0.05}\\\\k=49\ N/m$

So, the spring constant of the spring is 49 N/m.

8 0

3 years ago

A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loo

m_a_m_a [10]

Answer:

The induced emf is $\epsilon = 0.1041 \ V$

Explanation:

From the question we are told that

The radius of the circular loop is $r = 9.50 \ cm = 0.095 \ m$

The intensity of the wave is $I = 0.0215 \ W/m^2$

The wavelength is $\lambda = 6.90\ m$

Generally the intensity is mathematically represented as

$I = \frac{ c * B^2 }{ 2 * \mu_o }$

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4 \pi *10^{-7} N/A^2$

B is the magnetic field which can be mathematically represented from the equation as

$B = \sqrt{ \frac{ 2 * \mu_o * I }{ c} }$

substituting values

$B = \sqrt{ \frac{ 2 * 4\pi *10^{-7} * 0.0215 }{ 3.0*10^{8}} }$

$B = 1.342 *10^{-8} \ T$

The area is mathematically represented as

$A = \pi r^2$

substituting values

$A = 3.142 * (0.095)^2$

$A = 0.0284$

The angular velocity is mathematically represented as

$w = 2 * \pi * \frac{c}{\lambda }$

substituting values

$w = 2 * 3.142 * \frac{3.0*10^{8}}{ 6.90 }$

$w = 2.732 *10^{8} rad \ s^{-1}$

Generally the induced emf is mathematically represented as

$\epsilon = N * B * A * w * sin (wt )$

At maximum induced emf $sin (wt) = 1$

So

$\epsilon = N * B * A * w$

substituting values

$\epsilon = 1 * 1.342 *10^{-8} * 0.0284 *2.732 *10^{8}$

$\epsilon = 0.1041 \ V$

7 0

3 years ago