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inysia [295]
3 years ago
5

A train A travelled a distance of 150 km in 3 hours, whereas, train 'B"

Physics
1 answer:
ozzi3 years ago
8 0

Answer:

Therefore, Train A is faster with 50km/h and a 5km/h difference

Explanation:

train A

150km/3h = 50km/h

train B

180km/4h = 45km/h

You might be interested in
A bottle rocket takes off with a = 34.5 m/s2. It
sergiy2304 [10]

Answer:3.4 seconds

Explanation:

Initial velocity(u)=0

acceleration=34.5m/s^2

Height(h)=200m

Time =t

h=u x t - (gxt^2)/2

200=0xt+(34.5xt^2)/2

200=34.5t^2/2

Cross multiply

200x2=34.5t^2

400=34.5t^2

Divide both sides by 34.5

400/34.5=34.5t^2/34.5

11.59=t^2

t^2=11.59

Take them square root of both sides

t=√(11.59)

t=3.4 seconds

8 0
3 years ago
What is the force required to move a block of mass 150 pound by a distance of 5ft in 8 seconds?
Nadusha1986 [10]

Force required to move a block is 1.615 N

Given:

mass of block = m = 150 pounds = 68 kg

distance = d = 5 ft = 1.52 metres

time = t = 8 sec

To Find:

force required to move the block

Solution: Force is defined as product of mass and acceleration and it's unit is N or Newton.

Velocity = displacement/ time = 1.52 / 8 = 0.19 m/s

Acceleration = velocity/time = 0.19/8 =

0.023 m/s^2

Force = mass x acceleration = 68x0.023 = 1.615 N

Hence, force required to move the block is 1.615 N

Learn more about Force here:

brainly.com/question/12970081

#SPJ4

8 0
1 year ago
What was the largest group in the colonies in the year leading up to the American revoulation
Degger [83]
Answer: The English origin was the largest

7 0
2 years ago
Read 2 more answers
Who discovered the basic laws of planetary orbits?.
saveliy_v [14]

Answer:

Johannes Kepler

3 0
2 years ago
The resistance of a very fine aluminum wire with a 20 μm × 20 μm square cross section is 1200 Ω . A 1200 Ω resistor is made by w
notsponge [240]

Explanation:

The given data is as follows.

         Resistance (R) = 1200 ohm,     Area (A) = 20 \times 10^{-6} m (as 1 \mu m = 10^{-6} m)

            Diameter (d) = 2.3 mm = 2.3 \times 10^{-3} m

First, we will calculate the length as follows.

            R = \rho \frac{L}{A}

Here,  \rho = resistivity of aluminium = 2.65 \times 10^{-8}

Putting the given values above and we will calculate the value of length as follows.

               R = \rho \frac{L}{A}

             1200 = 2.65 \times 10^{-8} \times \frac{L}{20 \times 10^{-6}}

               L = 9.056 \times 10^{5}

As the circumference of circular wire = 2 \pi r

or,                                                          = 2 \times \pi \times \frac{d}{2}  

                                                              = \pi \times d

And, number of turns will be calculated as follows.

             No. of turns × Circumference = Length of wire

              No. of turns × 3.14 \times 2.3 \times 10^{-3} = 9.056 \times 10^{5}

                               = 1.25 \times 10^{8}

Thus, we can conclude that 1.25 \times 10^{8}  turns of wire are needed.

6 0
2 years ago
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