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3 years ago

5

234 oz to tons using the table method (US)

1 answer:

Rom4ik [11]3 years ago

3 0

Answer:

234 oz = 0.0066339 t.

Explanation:

Boom Logic...

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If a sound wave travels through air at a speed of 345 m/s, what would be the frequency of a 0.80 m long wave?

den301095 [7]

Answer:

D

Explanation:431.3

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3 years ago

Why do you think that the speeds of comets increase as they near the sun

Lina20 [59]

Because the force of gravity attracts the comets towards the sun

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4 years ago

The given function represents the position of a particle traveling along a horizontal line. s(t) = 2t3 − 3t2 − 36t + 6 for t ≥ 0

igor_vitrenko [27]

1) The velocity of the particle is given by the derivative of the position. So, if we derive s(t), we get the velocity of the particle as a function of the time:

$v(t)=s'(t)=(2t^3-3t^2-36t+6)'=6t^2-6t-36$

2) The acceleration of the particle is given by the derivative of the velocity. So, if we derive v(t), we get the acceleration of the particle as a function of the time:

$a(t)=v'(t)=(6t^2-6t-36)'=12t-6$

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4 years ago

One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other wor

zhannawk [14.2K]

Answer:

Part a)

v = 16.52 m/s

Part b)

v = 7.47 m/s

Explanation:

Part a)

(a) when the large-mass object is the one moving initially

So here we can use momentum conservation as the net force on the system of two masses will be zero

so here we can say

$m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v$

since this is a perfect inelastic collision so after collision both balls will move together with same speed

so here we can say

$v = \frac{(m_1v_{1i} + m_2v_{2i})}{(m_1 + m_2)}$

$v = \frac{(8.4\times 24 + 3.8\times 0)}{3.8 + 8.4}$

$v = 16.52 m/s$

Part b)

(b) when the small-mass object is the one moving initially

here also we can use momentum conservation as the net force on the system of two masses will be zero

so here we can say

$m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v$

Again this is a perfect inelastic collision so after collision both balls will move together with same speed

so here we can say

$v = \frac{(m_1v_{1i} + m_2v_{2i})}{(m_1 + m_2)}$

$v = \frac{(8.4\times 0 + 3.8\times 24)}{3.8 + 8.4}$

$v = 7.47 m/s$

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3 years ago

What will be the final velocity of a 5.0 g bullet starting from rest, if a net force of 45 N is

djverab [1.8K]

The net force performs a total amount of work equal to

(45 N) (0.80 m) = 36 J

on the bullet, and this is in turn is equal to the change in the bullet's kinetic energy by the work-energy theorem. So we have

W = ∆K = 1/2 mv²

since the bullet starts at rest, where m = its mass and v = its final velocity.

Solve for v :

36 J = 1/2 (0.0050 kg) v² ⇒ v = 120 m/s

5 0

2 years ago