Answer:
a₂ = 1.9 m/s²
Explanation:
Newton's third law or principle of action and reaction :
Force of the boy on the girl = - Force of the girl on the boy
Fbg = - Fgb Formula (1)
Newton's second law
∑F = m*a Formula (2)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Newton's second law to the girl
m₁ : girl mass
a₁ : acceleration of the girl toward the boy
∑F = m₁*a₁
Fbg= (40kg)*(3 m/s²)
Fbg = 120 N
Newton's second law to the boy
m₂: boy mass
a₂ : acceleration of the boy toward the girl
∑F = m₂*a₂
Fgb = (63)*a₂
120 = (63)*a₂
a₂ = 120 / (63)
a₂ = 1.9 m/s²
Answer:
577g
Explanation:
Given parameters:
Temperature change = 5.9°C
Amount of heat lost = 427J
Unknown:
Mass of the block = ?
Solution:
The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.
H = m c Ф
H is the heat capacity
m is the mass of the block
c is the specific heat capacity
Ф is the temperature change
Specific heat capacity of lead is 0.126J/g°C
m = H / m Ф
m =
= 577g
Mass of the lead block is 577g
Aerospace engineering is responsible for a plane design
There are no correct descriptive statement on the list you included.
Answer:
- <u>The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.</u>
Explanation:
The motions of the two water ballons are ruled by the kinematic equations:
We are only interested in the vertical motion, so that equation is all what you need.
<u>1. Water ballon is thrown horizontally at sped 2.00 m/s.</u>
The time the ballon takes to hit the ground is independent of the horizontal speed.
Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.
Then:

<u>2. Water ballon thrown straight down at 2.00 m/s</u>
Now the initial vertical speed is 2.00 m/s down. So, the equation is:

To solve the equation you can use the quadratic formula.

You get two times. One of the times is negative, thus it does not have physical meaning.
<u>3. Conclusion:</u>
The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.