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Viktor [21]
3 years ago
12

A golf ball (m=26.7g) is struck a blow that makes an angle of 33.6 degrees with the horizontal. The drive lands 190m away on a f

lat fairway. The acceleration of gravity is 9.8 m/s^2 . If the golf club and ball are in contact for 7.13 ms, what is the average force of impact?
Physics
1 answer:
koban [17]3 years ago
4 0

Answer:

Th average force impact is F = 168.298 \  N

Explanation:

From the question we are told that  

   The mass of the golf ball is  m_g =  26.7 \  g  =  0.0267 \  kg

    The angle made is \theta =  33.6 ^o

    The range of the golf ball  is R =  190 \  m

     The duration of contact is \Delta  t =  7.13 \  ms = 7.13 *10^{-3} \ s

Generally the range of the golf ball is mathematically represented as

       R = \frac{v^2 sin2(\theta)}{g}

Here v  is the velocity with which the golf club propelled it with, making  v the subject

       v  =  \sqrt{\frac{R *  g}{sin 2 (\theta)} }

=>     v  =  \sqrt{\frac{190 *  9.8}{sin 2 (33.6)} }

=>     v  =  44.94 \  m/s

Generally the change in momentum of the golf ball is mathematically represented as

      \Delta p  =  m  *  (v - u )

here u  is the initial  velocity of the ball before being stroked and the value is 0 m/s

       \Delta p  =  0.0267  *  ( 44.94 - 0 )

=>    \Delta p  = 1.19996 \  kg \cdot m/s

Generally the  average force of impact is mathematically represented as      

         F = \frac{\Delta  p }{\Delta t}

=>        F = \frac{1.19996 }{7.13 *10^{-3}}

=>        F = 168.298 \  N

     

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Puck 1 (1 kg) travels with velocity 20 m/s to the right when it collides with puck 2 (1 kg) which is initially at rest. After th
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Answer:

Explanation:

Parameters given:

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Initial velocity of Puck 2, U = 0 m/s

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Since we are told that momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum of the system = Total final momentum of the system

mu + MU = mv + MV

(1 * 20) + (1 * 0) = (1 * 5) + (1 * V)

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This is an object's change in motion per unit time in a specified direction.
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Velocity is an object's change in motion per unit time in a specified direction

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A) 8.11 m/s

For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}

where

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R is the radius of the asteroide

h is the altitude of the satellite

G is the gravitational constant

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Solving the equation for v, we find

v=\sqrt{\frac{GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

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Substituting into the formula,

v=\sqrt{\frac{(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=8.11 m/s

B) 11.47 m/s

The escape speed of an object from the surface of a planet/asteroid is given by

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