A probe orbiting Venus exerts a gravitational force of 2.58 × 10^3 N on Venus. Venus has a mass of 4.87 × 10^24 kg. The mass of
1 answer:
So this is the info that's given to us:
m1 = 4.87 x 10^24 kg
m2 = 4.87 x 10^24kg
F = 2.58 x 10^3 N
Now we can use this equation to solve:
You may be asking what g is. Well, it is equal to 6.67x10^-11 m3 /kg s2. G is gravitational constant. So :
As you can see we only have one variable, so we solve for r!
I hope this helps you out. I remember when I was first learning Newton's law<span> of universal </span><span>gravitation and I had some trouble. But with some practice, I got better. =) </span>
m1 = 4.87 x 10^24 kg
m2 = 4.87 x 10^24kg
F = 2.58 x 10^3 N
Now we can use this equation to solve:
You may be asking what g is. Well, it is equal to 6.67x10^-11 m3 /kg s2. G is gravitational constant. So :
As you can see we only have one variable, so we solve for r!
I hope this helps you out. I remember when I was first learning Newton's law<span> of universal </span><span>gravitation and I had some trouble. But with some practice, I got better. =) </span>
You might be interested in
For the work-energy theorem, the work needed to stop the bus is equal to its variation of kinetic energy:
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus
Since the bus comes at rest, its final kinetic energy is zero:
, so the work done by the brakes to stop the bus is
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus
Since the bus comes at rest, its final kinetic energy is zero:
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.