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Jlenok [28]
3 years ago
14

Define projectile in your own .​

Physics
2 answers:
vazorg [7]3 years ago
8 0

Answer:

<h3><em>projectile is defined as a body thrown in space , moves under the influence of gravity .</em></h3>

<em>hope</em><em> it</em><em> is</em><em> </em><em>you </em>

lorasvet [3.4K]3 years ago
5 0

Answer:

a body which was thrown in space ,moves under the influence of gravity only is defined as projectile.

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1 volt = 1 joule per coulomb 50 volts = 50 joules per coulomb 50 joules/coulomb times 6 coulombs = 300 joules
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This reaction appears to be destroying the logs. when it is over only ash will remain, the law of conservation of mass tells us
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At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 25 cm on a spring with a spring con
KiRa [710]

Answer:

0.11m/s

Explanation:

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Kinetic Energy = Elastic potential energy

KE = SE

\frac{1}{2}mv^2 = \frac{1}{2}kX^2

Where,

m=mass

v=velocity

k=spring constant

x=amount of compression

Re-arrange the equation to find the velocity we have,

v^2 = \frac{kX^2}{m}

v^2 = \frac{10(0.25)^2}{50}

v = \sqrt{0.0125}

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8 0
3 years ago
The record distance in the sport of throwing cowpats is 81.1 m. This record toss was set by Steve Urner of the United States in
N76 [4]

Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

d=\frac{v^2}{g}sin 2\theta

where

v is the initial speed

g = 9.8 m/s^2 is the acceleration of gravity

\theta is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

\theta=45^{\circ} is the angle

Solving for v, we find the speed of the projectile:

v=\sqrt{\frac{dg}{sin 2 \theta}}=\sqrt{\frac{(81.1 m)(9.8 m/s^2)}{sin (2\cdot 45^{\circ})}}=28.2 m/s

7 0
3 years ago
PLEASE HELP ME ON THIS ONE ANYONE
andreev551 [17]

Answer:

A & B

Explanation:

A & B Would be the right answer since Morse code cannot be represented through the height of the fire.

6 0
2 years ago
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