Answer:50.39 m/s,
40.46 m
Explanation:
Given
launch angle
Range=240 m
We know that Range 

u=50.39 m/s
(b)maximum height of projectile is given by


H=40.46 m
The quantum mechanical model describes the allowed energies an electron can have. It also describes how likely it is to find the electrons in various locations around an atom's nucleus.
Answer:
1845.26 ?
Explanation:
18.46 × 99.96= 1845.2616 = 1845.26
im not entirely sure though
In order to measure the size of the electrical current flowing in the circuit,
the current must pass through the meter.