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Anna71 [15]
4 years ago
10

Una lancha sube y baja por el paso de las olas cada 3.2 segundos, entre cresta y cresta hay una distancia de 24.5 m. ¿cual es la

rapidez con la que se mueven las olas?
Physics
1 answer:
Andrei [34K]4 years ago
7 0

Answer:

7.656 m/s

Explanation:

El sonido viaja a cierta velocidad y tiene una frecuencia y longitud de onda. La relación entre la velocidad del sonido (V), su frecuencia (f) y la longitud de onda (λ) es la misma que para todas las ondas, está dada por la ecuación:

V = fλ

pero f = 1/T

∴ V = λ/T

donde T es el período

Dado que:

período (T) es el tiempo necesario para subir y bajar = 3.2 s

La distancia entre dos crestas es la longitud de onda (λ) = 24.5 m

V =  λ/T = 24.5 / 3.2 = 7.656 m/s

V = 7.656 m/s

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Vinvika [58]

Answer:

Ball hit the tall building 50 m away below 10.20 m its original level

Explanation:

Horizontal speed = 20 cos40 = 15.32 m/s

Horizontal displacement = 50 m

Horizontal acceleration = 0 m/s²

Substituting in s = ut + 0.5at²

    50 = 15.32 t + 0.5 x 0 x t²

     t = 3.26 s

Now we need to find how much vertical distance ball travels in 3.26 s.

Initial vertical speed  = 20 sin40 = 12.86 m/s

Time = 3.26 s

Vertical acceleration = -9.81 m/s²

Substituting in s = ut + 0.5at²

    s = 12.86 x 3.26 + 0.5 x -9.81 x 3.26²

    s = -10.20 m

So ball hit the tall building 50 m away below 10.20 m its original level

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3 years ago
What did Rutherford’s model of the atom include that Thomson’s model did not have?
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3 years ago
The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron
FrozenT [24]

Answer:

<em>Speed of the electron is 2.46 x 10^8 m/s</em>

<em></em>

Explanation:

momentum of the electron before relativistic effect = M_{0} V

where M_{0} is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = M_{0}/ \sqrt{1 - \beta ^{2}  }

where

\beta = V/c

c  is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> M_{0}V/ \sqrt{1 - \beta ^{2}  }

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75M_{0} V = M_{0}V/ \sqrt{1 - \beta ^{2}  }

the equation reduces to

1.75 = 1/ \sqrt{1 - \beta ^{2}  }

square both sides of the equation, we have

3.0625 = 1/(1 - \beta ^{2} )

3.0625 - 3.0625\beta ^{2} = 1

2.0625 = 3.0625\beta ^{2}

\beta ^{2} = 0.67

β = 0.819

substitute for  \beta = V/c

V/c = 0.819

V = c x 0.819

V = 3 x 10^8 x 0.819 = <em>2.46 x 10^8 m/s</em>

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3 years ago
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