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nataly862011 [7]
3 years ago
12

PLEASE ANSWER

Chemistry
1 answer:
yuradex [85]3 years ago
6 0

D. Even though the temperature is the same, container B has more thermal energy, since it has more liquid than container A.

<u>Explanation: </u>

Whenever there is an increase in the volume of the pink liquid, it is due to the increase in temperature.

When the temperature increases, the molecules move farther apart as much as possible.

When the molecules moves apart from each other and collide with each other, so that its kinetic energy also increases, So thermal energy of the container B is more compared to the container A.

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Finish this formula: Speed = _______ divided by time
Alexus [3.1K]

Answer:

Distance

Explanation:

Speed= Distance/ Time

7 0
3 years ago
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Which of the following best explains velocity?
zhannawk [14.2K]
Velocity is explained as the *speed and *direction something might move.  Speed means moving and Direction means a certain way (not stationary.)

Hope this helps!
8 0
2 years ago
A 2.5% (by mass) solution concentration signifies that there is of solute in every 100 g of solution. 2. therefore, when 2.5% is
densk [106]
Answer #1 is "there is 2.5 grams of solute in every 100 g of solution." 
We calculate for 2.5% by mass solution by dividing the mass of the solute by the mass of the solution and then multiply by 100.
Answer #2 is "that mass ratio would be 2.5/100 or 2.5 grams of solute/100 grams of solution." 
We weigh out 2.5 grams of solute and then add 97.5 grams of solvent to make a total of 100 gram solution, that is,
     mass of solute / mass of solution = 2.5g solute / (2.5g solute + 97.5g solvent)
                                                          = 2.5g solute / 100g solution
Answer#3 is "a solution mass of 1 kg is 10 times greater than 100 g, thus one kilogram (1 kg) of a 2.5% ki solution would contain 25 grams of ki."
We multiply 10 to each mass so that 100 grams becomes 1000grams since 1000 grams is equal to 1 kg:
     mass of solute / mass of solution = 2.5g*10/[(2.5g*10) + (97.5g*10)]
                                                          = 25g solute/(25g solute + 975g solvent)
                                                          = 25g solute/1000g solution
                                                          = 25g solute/1kg solution
5 0
3 years ago
Read 2 more answers
a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what
jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in liters.

n - Molar quantity, measured in moles.

T - Temperature, measured in Kelvin.

R_{u} - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}} (2)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

V_{1}, V_{2} - Initial and final volume, measured in liters.

T_{1}, T_{2} - Initial and final temperature, measured in Kelvin.

If we know that P_{1} = 121\,kPa, P_{2} = 202\,kPa, V_{1} = 2.7\,L, T_{1} = 288\,K and T_{2} = 303\,K, the final volume of the gas is:

V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}

V_{2} = 1.702\,L

The gas will occupy a volume of 1.702 liters.

6 0
3 years ago
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Olegator [25]
C_{3} H_{8} + 5 O_{2} ---\ \textgreater \  3CO_{2}  +4H_{2}O    (-2012 \frac{kJ}{mol} )&#10;&#10;&#10;3 mol                10 mol&#10;&#10;&#10;C_{3}H_{8} is /excess /reactant&#10;&#10;because 3 mol propane require 15 mol oxygen (by reaction)&#10;&#10;5 mol oxygen ---1 mol propane, so&#10;&#10;10 mol oxygen ---2 mol propane&#10;&#10;Only 2 mole propane will be burned,&#10;&#10;so &#10;&#10;2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off&#10;&#10;Correct answer is number 4.&#10;&#10;&#10;
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