The name of a binary compound ends with _____. A.-ine B.-ary C.-ed D.-ide

Chemistry

1 answer:

inn [45]3 years ago

7 0

Cant really explain, for say, but its D.-ide

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Use the "x is small" approximation to find the concentration of the products in the following reaction which initially contains

Mrrafil [7]

Answer:

Concentration of product at equilibrium ;

$[H^+]=0.0000229 M$

$[CN^-]=0.0000229 M$

Explanation:

$HCN(aq)\rightleftharpoons H^+(aq) + CN^-(aq)$

initially

0.85 M 0 0

(0.85-x)M x x

The equilibrium constant of reaction = $K_c= 6.17\times 10^{-10}$

The expression of an equilibrium cannot can be written as:

$K_c=\frac{[H^+][CN^-]}{[HCN]}$

$6.17\times 10^{-10}=\frac{x\times x}{(0.85-x)}$

Solving for x:

x = 0.0000229

Concentration of product at equilibrium ;

$[H^+]=0.0000229 M$

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4 0

3 years ago

Use the Henderson-Hasselbalch equation and your knowledge of ionization to help you answer this question. Aspirin is a weak acid

Leya [2.2K]

Answer:

The protonated form is predominant when aspirin is absorbed more readily. The ratio of conjugate base to acid is 1 to 100.

Explanation:

Aspirin is more readily absorbed when it is protonated, that is when pH is lower than pKa (<em>more H⁺ available in the medium</em>). We can confirm this using Henderson-Hasselbalch equation for pH = 1.5:

$pH = pKa +log(\frac{conjugate base}{weak acid} )\\1.5=3.5 +log(\frac{conjugate base}{weak acid} )\\-2.0=log(\frac{conjugate base}{weak acid} )\\10^{-2.0} =\frac{conjugate base}{weak acid}\\\frac{conjugate base}{weak acid}=0.01=\frac{1}{100}$