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a_sh-v [17]
3 years ago
11

Karen runs 8 miles in 84 minutes. At the same rate, how many minutes would she take to run 6 miles?

Mathematics
2 answers:
sammy [17]3 years ago
7 0
It will take 63 minutes to run 6 miles.
madam [21]3 years ago
6 0
Do 84 divided by 8 to get 10.5
multiply 6 and 10.5 to get 63
it would take 63 minutes to run 6 miles
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State A and state B are among the states with the most remaining drive in movie screens. State A has 4 more screens than state B
mojhsa [17]
State A has 25 drive-in movie screens and State B has 21. You find this by guess-and-checking different numbers that you could add together to get 46. You want to do numbers that are relatively close, as a difference in 4 is not much at all. You can divide 46 by 2 and then play around from there.
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2 years ago
Trigonometry questions
trasher [3.6K]

We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.

11.

Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.

tan B = b/a

b = a tan B = 65.7 tan 28.9° = 36.3 m

12.

Similar story, boat at B, opposite b=3.5 m, rope c=12 m

sin B = b/c

B = arcsin b/c = arcsin (3.5/12) = 17.0°

13.

c=124 m, A=58°

sin A = a/c

a = c sin A = 124 sin 58 = 105.2 m

14.

That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so

cos A = b/c

A = arccos b/c = arccos (1.8/2.8) = 50.0°

15.

Not a right triangle, an isosceles triangle.  Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°.  We're after d=2b:

sin B = b/c

b = c sin B

d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm

Almost equilateral


4 0
3 years ago
A ball of mass 0.4 kg flies through the air at low speed, so that air resistance is negligible. What is the net force acting on
arsen [322]

Answer:

-3.92 N

Step-by-step explanation:

We are given that

Mass of ball=0.4 kg

Acceleration due to gravity=-9.8m/s^2

Because the ball flies against to gravity

We have to find the net force acting on the ball while it is in motion.

We know that when there is no air resistance then the net  force acts on the ball is equal to weight of ball.

Net force,F =mg

Substitute the values then we get

F=0.4(-9.8)

F=-3.92N

Hence, the net force acting on the ball while it is on motion=-3.92 N

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