A worker pushes horizontally on a large crate with a force of 265 n and the crate is moved 4.5 M how much work was done
1 answer:
You might be interested in
displacement is given by equation
now at t = 5 s the position is
similarly position at t = 9 s
so the displacement of object in given interval of time will be
time interval
now the average velocity will be given as
so its average speed is 252 m/s
Answer:
W = 1250 J = 1.25 KJ
Explanation:
The work done by the boy is due to the change in the position of the cement vertically. Hence, the work done in this case will be equal to the potential energy of the cement:
where,
W = Work done = ?
mg = W = weight of cement = 500 N
h = height covered = 2.5 m
Therefore,
<u>W = 1250 J = 1.25 KJ</u>