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Nutka1998 [239]
3 years ago
5

An astronomer discovers an object at a distance of 28 Mpc from the Earth. (Recall, M-prefix meaning Mega, i.e. times 106 ) At th

is distance, what is the object most likely to be?
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

The object is most likely to be a (distant) galaxy

Explanation:

Distance of galaxies are often calculated based on the unit of light year.

The abbreviation, mpc which translates to mega parsec

A mega parsec is equivalent to 3.3 light years.

So, if the astronomer sighted the object from a distance of 28mpc which is equivalent to 28 * 3.3 light-years (92.4 light years); the object is most likely to be a galaxy; a distant galaxy

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Which describes the electric field at the center of a ring of uniform negative charge?.
Bingel [31]

Answer:

A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge Q as shown in the following figure. The particle, confined to move along the x axis, is moved a small distance x along the axis ( where x << a) and released. Show that the particle oscillates in simple harmonic motion with a frequency given by,

7 0
2 years ago
Problem #3: 3.6. A diode has wdo = 0.4 µm and φj = 0.85 V. (a) What reverse bias is required to triple the depletion-layer width
Alchen [17]

Answer:

a) 6.8 Volt

b) 1.21Цm

Explanation:

We are given from the question that

   The zero -bias depletion layer width(W_{do}) is 0.4Цm

  The built in voltage φj  is 0.85V

Now to calculate the reverse voltage( V_{R}) that would be required  to triple the depletion - layer width.

  The depletion - layer width (W_{d}) of the diode has the formula

                          W_{d} = W_{do} \sqrt{1 + \frac{V_{R} }{Qj} }

    For three times of   W_{d} we have

        3W_{d} = W_{do} \sqrt{1 +\frac{V_{R} }{Qj} }

         =>      \frac{V_{R} }{Qj} = 3^{2} -1

        => V_{R} = 8Qj

        Substituting value of φj

       We have

                         V_{R} = 8(0.85V)

                               =   6.8 V

The required bias voltage  V_{R} is  6.8 V

   The solution for the b part of the question is uploaded on first image

7 0
3 years ago
How do I do this problem?
Aleks04 [339]

Use Charles Law: V1/T1 = V2/T2

0.30 m^3/27 C = V2/127 C

27V2 = 127 * 0.3

V2= 38.1/27 = 1.4 m^3

5 0
3 years ago
When did the ball fly farther—when it hit the moving bat or the bat that did not move?
8_murik_8 [283]

Answer:

when it hit the moving bat

Explanation:

force equals mass times acceleration which means the moving bat will add more force to the ball.

6 0
3 years ago
A 60.00-cm guitar string under a tension of 50.000 N has a mass per unit length of 0.100 00 g/cm chegg
Evgen [1.6K]

Fundamental frequency,

f=v2l=T/μ−−−−√2l

=(50)/0.1×10−3/10−22×0.6−−−−−−−−−−−−−−−−−−−√

=58.96Hz

Let, n th harmonic is the hightest frequency, then

(58.93)n = 20000

∴N=339.38

Hence, 339 is the highest frequency.

∴fmax=(339)(58.93)Hz=19977Hz.

<h3>What is frequency?</h3>

In physics, frequency is the number of waves that pass a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also simple harmonic motion and angular velocity.

learn more about frequency refer:

brainly.com/question/254161

#SPJ4

7 0
2 years ago
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