Answer:
A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge Q as shown in the following figure. The particle, confined to move along the x axis, is moved a small distance x along the axis ( where x << a) and released. Show that the particle oscillates in simple harmonic motion with a frequency given by,
Answer:
a) 6.8 Volt
b) 1.21Цm
Explanation:
We are given from the question that
The zero -bias depletion layer width(
) is 0.4Цm
The built in voltage φj is 0.85V
Now to calculate the reverse voltage( 
) that would be required to triple the depletion - layer width.
The depletion - layer width (
) of the diode has the formula
For three times of we have
=> 
=> 
Substituting value of φj
We have
= 6.8 V
The required bias voltage is 6.8 V
The solution for the b part of the question is uploaded on first image
Use Charles Law: V1/T1 = V2/T2
0.30 m^3/27 C = V2/127 C
27V2 = 127 * 0.3
V2= 38.1/27 = 1.4 m^3
Answer:
when it hit the moving bat
Explanation:
force equals mass times acceleration which means the moving bat will add more force to the ball.
Fundamental frequency,
f=v2l=T/μ−−−−√2l
=(50)/0.1×10−3/10−22×0.6−−−−−−−−−−−−−−−−−−−√
=58.96Hz
Let, n th harmonic is the hightest frequency, then
(58.93)n = 20000
∴N=339.38
Hence, 339 is the highest frequency.
∴fmax=(339)(58.93)Hz=19977Hz.
<h3>
What is frequency?</h3>
In physics, frequency is the number of waves that pass a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also simple harmonic motion and angular velocity.
learn more about frequency refer:
brainly.com/question/254161
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