An astronomer discovers an object at a distance of 28 Mpc from the Earth. (Recall, M-prefix meaning Mega, i.e. times 106 ) At th
1 answer:
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Answer:
Engular velocity:
Linear velocity:
The time it takes:
Explanation:
The magnitude of the centripetal acceleration can be related to the angular velocity and radius as:
(1)
Solving for w:
(2)
Replacing a=9,8m/s2 and r=6,375,000m:
(3)
And the angular velocity relates to the linear velocity:
The perimeter of the orbit is:
The time it takes:
initially, the car is traveling at 5.0 m/s.
so, we know acceleration for changing velocity is :
a = (v-v)/t ..........(i)
where v is the final velocity
v is the initial velocity
t is the time taken to change velocity
Now, as per the question :
initial velocity, v=5.0 m/s
final velocity, v =11 m/s
time taken, t = 3 s
putting the values in equation (i),
a = ( 11-5 )/3
a = 2 m/s²
Therefore, a, after 3 s, is <em>2 m/s².</em>
Answer:
The wavelength of the light is 633 nm.
Explanation:
Given that,
Distance between the two slits d= 0.025 cm
Distance between the screen and slits D = 120 cm
Distance between the slits y= 1.52 cm
We need to calculate the angle
Using formula of double slit
Where, y = Distance between the slits
D = Distance between the screen and slits
Put the value into the formula
We need to calculate the wavelength
Using formula of wavelength
Put the value into the formula
Hence, The wavelength of the light is 633 nm.