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Nutka1998 [239]
3 years ago
5

An astronomer discovers an object at a distance of 28 Mpc from the Earth. (Recall, M-prefix meaning Mega, i.e. times 106 ) At th

is distance, what is the object most likely to be?
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

The object is most likely to be a (distant) galaxy

Explanation:

Distance of galaxies are often calculated based on the unit of light year.

The abbreviation, mpc which translates to mega parsec

A mega parsec is equivalent to 3.3 light years.

So, if the astronomer sighted the object from a distance of 28mpc which is equivalent to 28 * 3.3 light-years (92.4 light years); the object is most likely to be a galaxy; a distant galaxy

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As 390-g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment.
stiks02 [169]
Q = m.s.Δt
Δt = Q /m.s
Here, Q = 30,000 J
m = 390 g
s = 3.9 J/g C

Substitute their values, 
 = 30,000 / 390 *3.9
 = 30,000 / 1521
 = -20 C (approx.)  [-ve sign 'cause temperature is decreasing ]

In short, Your Answer would be Option D

Hope this helps!

7 0
3 years ago
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Atividade 1) A presença do campo magnético terrestre proporciona alguns efeitos interessantes. Dentre eles estão as auroras pola
VLD [36.1K]
The answer is 1 the first one is the only one that makes sense
7 0
3 years ago
PLEASE HELP !
Bumek [7]

Answer:

gravitational potenetial energy =ℎ

Explanation:

none

5 0
3 years ago
Compared to gamma rays, X–rays have relatively
solniwko [45]
Gamma rays are known to have the greatest frequency and the shortest wavelength. What we also know is that frequency and energy are directly proportional (they are the same), and that the wavelength is the opposite of them - if frequency/energy are high, the wavelength will be short, and vice versa.
Since X-rays are the opposite of gamma rays, then the correct answer is the third option <u />- <u>less energy and long wavelengths.</u>
8 0
4 years ago
Read 2 more answers
If two similar large plates each of area having surface charge density is +a and -b are separated by a distance d in air find th
leva [86]

Answer:

a. V = (a - b)d/2ε₀ b. 2ε₀A/d

Explanation:

a. The potential difference between the plates

Using Gauss' law, we first find the electric field between the plates

ε₀∫E.dA = Q where Q = charge enclosed, E = electric field

Now Q = [a +(-b)]A = (a - b)A where + a and -b are the surface charge densities of the plates and A is the area of the plates.

ε₀∫E.dA = Q

ε₀∫EdAcos0 + ε₀∫EdAcos0 = (a - b)A

ε₀E∫dA + ε₀E∫dA = (a -b)A

ε₀EA + ε₀EA = (a -b)A

2ε₀EA = (a -b)A

E = (a - b)/2ε₀

We now find the potential difference, V between the plates from

V = ∫E.dl

V =E∫dl

V = Ed  where ∫dl = d the distance between the plates.

V = (a - b)d/2ε₀

b. The capacitance between them

Capacitance C = Q/V

= (a - b)A ÷ (a - b)d/2ε₀

= 2ε₀A/d

5 0
3 years ago
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