1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nutka1998 [239]
3 years ago
5

An astronomer discovers an object at a distance of 28 Mpc from the Earth. (Recall, M-prefix meaning Mega, i.e. times 106 ) At th

is distance, what is the object most likely to be?
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

The object is most likely to be a (distant) galaxy

Explanation:

Distance of galaxies are often calculated based on the unit of light year.

The abbreviation, mpc which translates to mega parsec

A mega parsec is equivalent to 3.3 light years.

So, if the astronomer sighted the object from a distance of 28mpc which is equivalent to 28 * 3.3 light-years (92.4 light years); the object is most likely to be a galaxy; a distant galaxy

You might be interested in
Given the displacement vector D = (4î − 8ĵ) m, find the displacement vector R (in m) so that D + R = −3Dĵ. (Express your answer
Elena-2011 [213]

Answer:

--------------------------------

Explanation:

4 0
3 years ago
Give examples of plants that can reproduce by vegetative reproduction.​
marishachu [46]

Answer:

Some examples of vegetative propagation are farmers creating repeated crops of apples, corn, mangoes or avocados through asexual plant reproduction rather than planting seeds. Vegetative propagation can be accomplished from side-shoots, slips, stems and sections of tubers, bulbs or rhizomes.

Explanation:

5 0
3 years ago
Se um corpo 1 está em movimento em relação a um corpo 2, e se o corpo 2 está em repouso em relação a um corpo 3, pode-se afirmar
stealth61 [152]
Yo habla ingles no espanol
8 0
3 years ago
Read 2 more answers
The position of a dragonfly that is flying parallel to the ground is given as a function of time by r⃗ =[2.90m+(0.0900m/s2)t2]i^
Arlecino [84]

The solution for this problem is:

 
r = [(2.90 + 0.0900t²) i - 0.0150t³ j] m/s² 
this is for t in seconds and r in meters 

v = dr/dt = [0.180t i - 0.0450t² j] m/s² 

tan(-36.0º) = -0.0450t² / 0.180t 
0.7265 = 0.25t 
t = 2.91 s is the velocity vector of the insect

7 0
2 years ago
Read 2 more answers
A 53.0-kg skater is traveling due east at a speed of 2.90 m/s. A 72.0-kg skater is moving due south at a speed of 6.20 m/s. They
soldier1979 [14.2K]

Answer:

a.\thta=71^{\circ}

b.v_f=3.78 m/s

Explanation:

We are given that

m_1=53 kg

v_1=2.9 m/s

m_2= 72 kg

v_2=6.2 m/s

a.We have to find the angle

\theta=tan^{-1}{\frac{m_2v_2}{m_1v_1}=\frac{72(6.2)}{53(2.9)}=71^{\circ}

\theta=71^{\circ}

b. We have to find the speed v_f

According to law of conservation of momentum

m_1v_1=(m_1+m_2)v_fcos\theta

53(2.9)=(53+72)v_fcos 71^{\circ}=40.7 v_f

v_f=\frac{153.7}{40.7}=3.78 m/s

3 0
3 years ago
Other questions:
  • A hypothetical spherical planet consists entirely of iron. what is the period of a satellite that orbits this planet just above
    15·1 answer
  • A balloon starts rising from rest from the ground with an acceleration of 1.25 m/s2. After 8s, a stone is released from the ball
    10·1 answer
  • Which of the following is not true about a good streching routines
    9·1 answer
  • If you attach a 50.0 g mass to the spring whose data are shown in the graph, what will be the period of its oscillations?
    10·1 answer
  • The acceleration due to gravity on earth will decrease as which of the following occurs. The mass of the object decreases. The d
    5·1 answer
  • Which process in the water cycle MUST occur directly before water can become groundwater?
    12·1 answer
  • As its speed increases, what happens to its energy of motion?
    5·1 answer
  • (4)science who ever gets this right will get a brainlest
    5·2 answers
  • What elements have similar behavior?
    10·1 answer
  • Plz help a smol bean out (no links btw)
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!