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Nutka1998 [239]
3 years ago
5

An astronomer discovers an object at a distance of 28 Mpc from the Earth. (Recall, M-prefix meaning Mega, i.e. times 106 ) At th

is distance, what is the object most likely to be?
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

The object is most likely to be a (distant) galaxy

Explanation:

Distance of galaxies are often calculated based on the unit of light year.

The abbreviation, mpc which translates to mega parsec

A mega parsec is equivalent to 3.3 light years.

So, if the astronomer sighted the object from a distance of 28mpc which is equivalent to 28 * 3.3 light-years (92.4 light years); the object is most likely to be a galaxy; a distant galaxy

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A(n) 82.7 kg boxer has his first match in the Canal Zone with gravitational acceleration 9.782 m/s 2 and his second match at the
Annette [7]

Answer:

82.7 kg

Explanation:

the mass of the boxer remains unchanged, this is because mass is a measure of the quantity of matter in an object irrespective of its location and the gravitational force acting at its location. this means mass is independent of the gravitational acceleration hence it remains the same 82.7 kg. its unit is in kilograms (Kg).

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3 years ago
Which of the following sentences shows the correct use of a transition word? Even though I was sick, I went to the doctor. My sh
Softa [21]

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D. I stayed up late for several nights. Eventually, I was too tired to concentrate.

Explanation:

i got it right edge 2020.

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3 years ago
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Which action might lead scientists to develop new explanations about the
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Answer:

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Explanation:

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3 years ago
Which statement is true about crystal lattice energy?
irinina [24]

The answer is:

It is a measure of the strength of the bonds between ions.

Lattice energy is an estimate of the strength of the bonds formed by ionic compounds.

The first two choices are wrong because it is actually the opposite.

  • As the ion size increases, lattice energy <u>decreases</u>.
  • As charge of ions increases, lattice energy <u>increases</u>

As for the other third option, it is wrong because lattice energy is the energy RELEASED not absorbed.

3 0
4 years ago
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The maximum stress in a section of a circular tube subject to a torque is τmax = 27 MPa . If the inner diameter is Di = 3.75 cm
DIA [1.3K]

Answer:

T_{max} = 4.735\,kN\cdot m

Explanation:

The shear stress due to torque can be calculed by using the following model:

\tau_{max} = \frac{T_{max}\cdot r_{ext}}{J_{tube}}

The maximum torque on the section is:

T_{max} = \frac{\tau_{max}\cdot J_{tube}}{r_{ext}}

The Torsion Constant for the circular tube is:

J_{tube} = \frac{\pi}{32}\cdot (D_{ext}^{4}-D_{int}^{4})

J_{tube} = \frac{\pi}{4}\cdot [(0.053\,m)^{4}-(0.038\,m)^{4}]

J_{tube} = 4.560\times 10^{-6}\,m^{4}

Now, the require output is computed:

T_{max} = \frac{(27\times 10^{3}\,kPa)\cdot (4.560\times 10^{-6}\,m^{4})}{0.026\,m}

T_{max} = 4.735\,kN\cdot m

7 0
3 years ago
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