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Mila [183]
3 years ago
11

Balanced forces acting on an object cause the object to accelerate. Please select the best answer from the choices provided T F

Physics
1 answer:
Pani-rosa [81]3 years ago
7 0
False
Balanced forces mean that there is no net force acting on the object. therefore, the object will not accelerate.
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What has to increase in order for an object to accelerate?
olga nikolaevna [1]

Answer:the force applied to the object

Explanation:

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4 years ago
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The human tibia breaks under an impulse of 55 Ns. If after falling a person typically comes to eat in a time span of 0.005 s how
ozzi

Answer:

0.73 m/s

Explanation:

From Newton second law of motion,

I = m(v-u)...................... Equation 1

Where I = Impulse, m = mass of the person, v = final velocity, u = Initial velocity.

make v the subject of the equation

v =(I/m)+u................. Equation 2

Note: u = 0 m/s as the person is falling from an height.

Given: I = 55 Ns, m = 75 kg, u = 0 m/s

Substitute into equation 2

v = 55/75

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4 years ago
Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 64.7 N64.7 N , Ji
WARRIOR [948]

Answer:

(a) Magnitude of force is 262.51 N

(b) Angle with East direction is -14.75^{o}

Explanation:

Force by Jack in vector form

\overrightarrow F _1} = 64.7{\rm{ N}}\left( {\hat i} \right)  

Force by Jill in Vector form is given by

\begin{array}{c}\\{\overrightarrow F _2} = 86.5{\rm{ N }}\cos {\rm{4}}{{\rm{5}}^{\rm{o}}}\left( {\hat i} \right) + 86.5{\rm{ N }}\sin {\rm{4}}{{\rm{5}}^{\rm{o}}}\left( {\widehat j} \right)\\\\ = 61.16{\rm{ N}}\left( {\hat i} \right) + 61.16{\rm{ N}}\left( {\widehat j} \right)\\\end{array}

Force by Jane is

\begin{array}{c}\\{\overrightarrow F _3} = 181{\rm{ N }}\cos {\rm{4}}{{\rm{5}}^{\rm{o}}}\left( {\hat i} \right) + 181{\rm{ N }}\sin {\rm{4}}{{\rm{5}}^{\rm{o}}}\left( { - \widehat j} \right)\\\\ = 128{\rm{ N}}\left( {\hat i} \right) + 128{\rm{ N}}\left( { - \widehat j} \right)\\\end{array}

Net force is:

\overrightarrow F = {\overrightarrow F _1} + {\overrightarrow F _2} + {\overrightarrow F _3}

Hence

\begin{array}{c}\\\overrightarrow F = 64.7{\rm{ N}}\left( {\hat i} \right) + 61.16{\rm{ N}}\left( {\hat i} \right) + 61.16{\rm{ N}}\left( {\widehat j} \right) + 128{\rm{ N}}\left( {\hat i} \right) + 128{\rm{ N}}\left( { - \widehat j} \right)\\\\ = 253.86{\rm{ N}}\left( {\hat i} \right) - 66.84{\rm{ N}}\left( {\widehat j} \right)\\\end{array}

The net force will be given by

F = \sqrt {{{\left( {{F_x}} \right)}^2} + {{\left( {{F_y}} \right)}^2}

Since F_{x}=253.86N and F_{y}=-66.84N

\begin{array}{c}\\F = \sqrt {{{\left( {253.86{\rm{ N}}} \right)}^2} + {{\left( { - 66.84{\rm{ N}}} \right)}^2}} \\\\ = {\bf{262.51 N}}\\\end{array}

The direction of net force is:

\theta = {\tan ^{ - 1}}\left {\frac{{{F_y}}}{{{F_x}}}}

Since F_{x}=253.86N and F_{y}=-66.84N  

\begin{array}{c}\\\theta = {\tan ^{ - 1}}\left( {\frac{{ - 66.84{\rm{ N}}}}{{253.86{\rm{ N}}}}} \right)\\\\ = {\tan ^{ - 1}}\left( { - 0.2633} \right)\\\\ = {\bf{ - 14}}{\bf{.7}}{{\bf{5}}^{\bf{o}}}\\\end{array}

The angle with East direction is -14.75^{o}

Net force exerted on the donkey is in the south-east direction. So, the angle of net force from the east direction is -14.75^{o} and it is 14.75^{o} from the south.

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Answer:

Yes, it is. The summers and the winters are getting warmer. Also in cold places like Alaska, the temperatures are rising.

Explanation:

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