Question

Not sure! help! please

Answer 1

$\dfrac{ \frac{x}{4} + \frac{1}{8} }{ \frac{x^2}{4} } = \vspace{3mm} = \dfrac{ \frac{2x}{8} + \frac{1}{8} }{\frac{x^2}{4}} \vspace{3mm} = \dfrac{ \frac{2x+1}{8} }{\frac{x^2}{4}} \vspace{3mm} = \dfrac{2x + 1}{8} \times \dfrac{4}{x^2} \vspace{3mm} = \dfrac{2x + 1}{2x^2}$