Answer: Elements are arranged from left to right and top to bottom in order of increasing atomic number.
Explanation: Order generally coincides with increasing atomic mass.
Answer:
to show how substances in a chemical reaction interact
to shorten the explanation of a chemical reaction
to help keep track of atoms in a chemical reaction
Explanation:
The axial positions the bond angle is 120 degrees and in equatorial positions the bond angle is 90 degrees.
Functional groups on central atom gets reduce if lone pairs are added.
Explanation:
The number of lone pairs and base pairs of electrons tells the geometry of the molecule.
VSEPR Theory helps to know the lone pairs and bond pair electrons on the centre atom of the molecule.
Example of molecule containing 5 electron pairs can have four bond pairs and 1 lone pair.
eg: Cl
the repulsion is shown as
lp-lp> lp-bp>bp-bp
These are in equatorial position because of the repulsion of lone pairs.
It can have 2 lone pairs and 3 bond pairs. eg. Xe
Lone pairs in this is also in equatorial position as
lp-lp> lp-bp> bp-bp
In axial positions the bond angle is 120 degrees
in equatorial positions the bond angle is 90 degrees, due to the repulsion in lone pair of electrons.
If 1 lone pair is there it can be replaced by bonding with hydrogen.
If 2 lone pairs are there then bonding with oxygen is there. The covalent bond is formed.
Answer:
ΔH = 2.68kJ/mol
Explanation:
The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:
q = m*S*ΔT
<em>Where q is heat of reaction in J,</em>
<em>m is the mass of the solution in g,</em>
<em>S is specific heat of the solution = 4.184J/g°C</em>
<em>ΔT is change in temperature = 11.21°C</em>
The mass of the solution is obtained from the volume and the density as follows:
150.0mL * (1.20g/mL) = 180.0g
Replacing:
q = 180.0g*4.184J/g°C*11.21°C
q = 8442J
q = 8.44kJ when 3.15 moles of the solid react.
The ΔH of the reaction is:
8.44kJ/3.15 mol
= 2.68kJ/mol