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VARVARA [1.3K]
3 years ago
5

3) In 5 electron group molecules, what is the difference between axial and equatorial positions? Which groups are removed as lon

e pairs are added?
Chemistry
1 answer:
shusha [124]3 years ago
7 0

The axial positions the bond angle is 120 degrees and in equatorial positions the bond angle is 90 degrees.

Functional groups on central atom gets reduce if lone pairs are added.

Explanation:

The number of lone pairs and base pairs of electrons tells the geometry of the molecule.

VSEPR Theory helps to know the lone pairs and bond pair electrons on the centre atom of the molecule.

Example of molecule containing 5 electron pairs can have four bond pairs and 1 lone pair.

eg: ClF_{3}

the repulsion is shown as

lp-lp> lp-bp>bp-bp

These are in equatorial position because of the repulsion of lone pairs.

It can have 2 lone pairs and 3 bond pairs. eg. XeF_{2}

Lone pairs in this is also in equatorial position as

lp-lp> lp-bp> bp-bp

In axial positions the bond angle is 120 degrees

in equatorial positions the bond angle is 90 degrees, due to the repulsion in  lone pair of electrons.

If 1 lone pair is there it can be replaced by bonding with hydrogen.

If 2 lone pairs are there then bonding with oxygen is there. The covalent bond is formed.

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Answer:

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Match the wave with its definition. (Lesson 4.03-4.03)
Lady_Fox [76]

The correct wave that matched its definition is:

  • Transverse Wave - A wave that has a disturbance that is perpendicular to the wave motion. The wave motion is moving side to side, the energy will be moving up and down.

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6 0
3 years ago
The highly reactive elements in group 7A are known for forming salts. What are they called?
iVinArrow [24]
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6 0
3 years ago
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2PbS(s) + 3O2(g)  2PbO(s) + 2SO2(g) H = -827.4 kJ What is the volume of sulfur dioxide produced at STP if 975 kJ of heat are l
Akimi4 [234]

Answer:

52.79 dm3 of SO2 will be produced when 975kJ/mol of heat are liberated.

Explanation:

In the reaction given;

2PbS(s) + 3O2(g)  2PbO(s) + 2SO2(g)                                H = -827.4 kJ/mol

-827.4 kJ/mol of heat liberates 2 moles of SO2 in the reaction involving lead and oxygen

At STP, -827.4 kJ/mol of heat liberate 22.4 * 2 dm3 of SO2

So therefore, 975 kJ/mol of heat will liberate

= 975 * 22.4 * 2 / -827.4

= 43 680 / -827.4

= 52.79 dm3 of SO2.

52.79 dm3 of SO2 will be produced at STP if 975 kJ/mol of heat are liberated.

6 0
3 years ago
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