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Andru [333]
3 years ago
10

In which pattern, periodic table was arranged?​

Chemistry
1 answer:
aksik [14]3 years ago
3 0

Answer: Elements are arranged from left to right and top to bottom in order of increasing atomic number.

Explanation: Order generally coincides with increasing atomic mass.

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Which element gains two electrons to fill its outermost energy level?
laiz [17]
O magnesium Mg is the answer
4 0
2 years ago
Part a the sun produces energy via fusion. one of the fusion reactions that occurs in the sun is 411h→42he+201e how much energy
Orlov [11]
The equation for the nuclear fusion reaction is,
4 ¹₁H → ₂⁴He + 2 ₁⁰e
Calculation of mass defect,
Δm = [mass of products - mass of reactants]
      = 4(1.00782) - [4.00260 + 2(0.00054858)]
      = 0.0275828 g/mole
Given that,
Mass of Hydrogen-1 = 2.58 g
The no. of moles of ₁¹H = 2.58 g / 1.00782 = 2.56 moles
Therefore, the mass defect for 2.58 g of ₁¹H is, 
= 2.56 moles * (0.0275828 g / 4) = 0.01765 x 10⁻³ kg
Energy for (0.01765 x 10⁻³ kg) is, 
= (0.01765 x 10⁻³ kg) (3.0 x 10⁸)² = 1.59 x 10¹² J
4 0
4 years ago
Read 2 more answers
A solution of citric acid (H₃C₆H₅O₇) with a known concentration of 0.200 M H₃C₆H₅O₇ is titrated with a 0.750 M NaOH solution. Ho
Anestetic [448]

The quantity of NaOH required to reach the third equivalence point is 20mL.

Using the titration formula,

CaVa/CbVb = Na/Nb

Where,

Ca = concentration of citric acid (0.200 M)

Cb = concentration of NaOH (0.750 M)

Va = Volume of citric acid (25.0 mL)

Vb = volume of NaOH (x mL)

Na = number of reacting mole of citric acid (3)

Nb = number of reacting mole of NaOH (1)

Therefore Vb ( x mL) =CaVaNb/CbNa

                                 

 = 0.2× 25×3/0.75 ×1

                                   

= 15/0.75

                   Vb ( x mL) = 20 mL

Learn more here:

brainly.com/question/23631409

8 0
3 years ago
A reaction rate assay measures enzyme _______________; and a colorimetric endpoint assay measures ________________.
VMariaS [17]

Answer:

The correct option is: A. activity; concentration

Explanation:

A reaction rate essay is a laboratory method to determine the activity of an enzyme. It is necessary for determining the enzyme kinetics and inhibition.

Whereas, a colorimetric analysis is a method to determine the concentration of a chemical compound in a solution. Therefore, a colorimetric endpoint assay measures the concentration.

Therefore, Enzyme activity is measured by a reaction rate assay and the concentration is measured by a colorimetric endpoint assay.

4 0
4 years ago
Read 2 more answers
Be sure to answer all parts. Hydrogen iodide decomposes according to the reaction 2 HI(g) ⇌ H2(g) + I2(g) A sealed 1.50−L contai
Zarrin [17]

Answer : The concentration of HI and I_2 at equilibrium is, 0.0158 M and 0.00302 M respectively.

Explanation :

First we have to calculate the concentration of H_2, I_2\text{ and }HI

\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.00623mol}{1.50L}=0.00415M

\text{Concentration of }I_2=\frac{\text{Moles of }I_2}{\text{Volume of solution}}=\frac{0.00414mol}{1.50L}=0.00276M

\text{Concentration of }HI=\frac{\text{Moles of }HI}{\text{Volume of solution}}=\frac{0.0244mol}{1.50L}=0.0163M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

                            2HI(g)\rightleftharpoons H_2(g)+I_2(g)

Initial conc.      0.0163     0.00415      0.00276

At eqm.        (0.0163-2x) (0.00415+x)  (0.00276+x)

As we are given:

Concentration of H_2 at equilibrium = 0.00467 M

That means,

(0.00415+x) = 0.00467

x = 0.00026 M

Concentration of HI at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M

Concentration of I_2 at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M

8 0
4 years ago
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