A drop of water from a special dropper is 3ml. How many liters is this this. A(30) B(0.3) C(0.03) D(0.003)

Helium decays to form lithium. Which equation correctly describes this decay? Superscript 6 Subscript 2 Baseline Upper H e right

Virty [35]

Answer:

Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper L i + Superscript 0 Subscript negative 1 Baseline e

Explanation:

Helium decays by beta emission, in beta emission, the mass number of the parent and daughter nuclei are the same but the atomic number of the daughter nucleus increases by one hence it is found one place to the right of its parent in the periodic table.

Having said this, the decay of Helium to lithium may be written as follows;

6/2He -> 6/3Li + 0/-1e

4 0

3 years ago

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The temperature of a 350. mL sample of gas increases from 27 °C to 227 °C. What is the final volume of the sample of gas, if the

Liono4ka [1.6K]

Answer:

$V_2=583.3mL$

Explanation:

Hello,

In this case, for the given constant amount and pressure of the, we apply the Charles' law which allows us to understand the volume-pressure behavior as a directly proportional relationship:

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Thus, since we need to compute the volume after the temperature increase (which must be expressed in absolute Kelvins), we obtain V2 as:

$V_2=\frac{V_1T_2}{T_1} =\frac{350.0mL*(227+273.15)K}{(27+273.15)K}\\ \\V_2=583.3mL$

Best regards.

5 0

3 years ago

Draw the conjugate bases of pyrrole and cyclopentadiene. Explain Why is the sp3 hybridized C―H bond of cyclopentadiene more acid

olga_2 [115]

Answer:

The explanations are given in the section below

Explanation:

First step:

We need to understand the acid-base equilibrium of the reaction. Bear in mind that the conjugate acid-base pairs are species that differ by one proton. Furthermore, one is a Lewis acid (meaning the ability to protons) and the conjugate base (accepts protons)

A simple conjugate base is obtained by removing one proton from an acid as shown below:

HX ⇄ A⁻ + H⁺

The diagrams are as follows: