All categories

3 years ago

How does precipitation grow by ice processes

1 answer:

3 0

Basically when frozen water/ice crystals high in the atmosphere collect water vapor molecules they grow. They are sometimes supplied by microscopic cloud droplets.

You might be interested in

What are alternative periodic tables

aksik [14]

Tabulations of chemical elements differing in their organization from the traditional seen periodic system

5 0

2 years ago

A scientist discovers a deep bowl-like divot under the ocean off the coast of eastern Mexico that is many kilometers across. The

arsen [322]

Answer:

its B

Explanation:

8 0

3 years ago

Read 2 more answers

The equation 1/2 N2 + 3/2 H2+ NH3 is not appropriately written because

Mrac [35]

Answer:

Madar choad sale kuuuta kamina

6 0

2 years ago

Scientists claim to be the way the continents were arranged 250 million years ago. Scientists who make this claim call this anci

Mkey [24]

Answer:

I dn't mnoefbv

Explanation:

6 0

2 years ago

Read 2 more answers

Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di

pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

$Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)$

Moles of calcium nitrate = $\frac{31.3 g}{164 g/mol}=0.1908 mol$

Moles of ammonium fluoride = $\frac{38.7 g}{37 g/mol}=1.046 mol$

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

$\frac{1}{2}\times 1.046 mol=0.523 mol$ calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

$\frac{2}{1}\times 0.1908 mol=0.3816 mol$ of dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant.

8 0

2 years ago