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Mazyrski [523]
3 years ago
13

What value of m makes this a true number sentence? m+3+m=3

Mathematics
1 answer:
MrRa [10]3 years ago
8 0
The correct value for m is 0(zero). :)
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In how many different ways can 4 students be seated with in a row?
DanielleElmas [232]
<span>4 people seated on a row may have 4! = 4x3x2x1 = 24 different ways to sit.</span>
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3 years ago
Please help me with precalculus??<br>linear and angular speed
Anit [1.1K]
13)

there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

\bf \cfrac{4\underline{\pi} }{5~\underline{s}}\cdot \cfrac{rev}{2\underline{\pi} }\cdot \cfrac{60~\underline{s}}{min}\implies \cfrac{4\cdot 60~rev}{5\cdot 2~min}\implies \cfrac{240~rev}{10~min}\implies 24\frac{rev}{min}

14)

 \bf \textit{linear velocity}\\\\&#10;v=rw\quad &#10;\begin{cases}&#10;r=radius\\&#10;w=angular~speed\\&#10;----------\\&#10;v=32\frac{m}{sec}\\&#10;w=100\frac{rev}{min}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\textit{let's convert \underline{w} to }\frac{radians}{sec}

\bf \cfrac{100~\underline{rev}}{\underline{min}}\cdot \cfrac{2\pi }{\underline{rev}}\cdot \cfrac{\underline{min}}{60~sec}\implies \cfrac{100\cdot 2\pi }{60~sec}\implies \cfrac{10\pi }{3~sec}\implies \cfrac{10\pi }{3}\frac{radians}{sec}\\\\&#10;-------------------------------\\\\&#10;v=rw\implies \cfrac{v}{w}=r\implies \cfrac{\frac{30~m}{sec}}{\frac{10\pi }{3~sec}}\implies r=\cfrac{30~m}{\underline{sec}}\cdot \cfrac{3~\underline{sec}}{10\pi }&#10;\\\\\\&#10;r=\cfrac{90}{10\pi }m

15)

what is the radians per seconds "w" in revolutions per minute?  just another conversion like in 13)

\bf \cfrac{\underline{\pi} }{3~\underline{sec}}\cdot \cfrac{rev}{2\underline{\pi }}\cdot \cfrac{60~\underline{sec}}{min}\implies \cfrac{60 ~rev}{3\cdot 2 ~min}\implies \cfrac{60 ~rev}{6 ~min}\implies 10\frac{rev}{min}
4 0
3 years ago
Please Help on Math question...
Eddi Din [679]

Answer:

Yes

Step-by-step explanation:

Because 9, 12, and 15 are Pythagorean triples

7 0
3 years ago
In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
3 years ago
Answer asap thank you!??!!??!
Semenov [28]
The answer to the problem is A
7 0
3 years ago
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