The balloon has a volume
dependent on its radius
:

Differentiating with respect to time
gives

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

The surface area of the balloon is

and differentiating gives

so that at the moment the radius is 3 m, its area is increasing at a rate of

Answer:
The height of the water = 6.2 in. to the nearest tenth
Step-by-step explanation:
∵ The rate of flows of water into the tank = 8000 in.³/min.
∴ The volume of the water in the tank after 10 min. = 8000 × 10 = 80000 in.³
∵ The water take the shape of the tank
∴ The height of the water = volume of water ÷ Area of the base of the tank
∵ The tank is cylinder with diameter 128 in. and height 72 in.
∴ The area of the base of the tank = π(128/2)²
∴ The height of the water = 
∴ The height of the water = 6.2 in. to the nearest tenth
Answer:
x=-16
Step-by-step explanation:
6x+12=4x-20
2x=-32
x=-16
Solution:
If the <u>numerator</u> and the <u>denominator</u> have like bases in exponents, then the <u>exponents</u> subtract.
- =>

Thus, 7b is the simplified expression.