Answer:
204.73K
Explanation:
the formula : PV=nRT
n=4
P=5.6 atm
V=12 L
R=0.08206 L atm mol-1 K-1
T=?
So, if you plug it in, you will get:-
T=PV/nR
T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)
T=204.73 K
hope this is correct!
Lar mass of Ca<span> = 40.08 </span>grams/mole 77.4 g Ca<span> * ( 1 </span>mole Ca<span>/ 40.08 ... n = m / M 1mol </span>Ca<span>weights 40 gmol-1 n = 77,4 / 40 = 1.93 </span>mol<span>.</span>
Fission is similar to mitosis because they both involve splitting.
Answer: <span><span>d. mitosis</span></span>
Answer:
105.8 g of Na would be required
Explanation:
Let's think the reaction:
2Na(s) + Cl₂(g) → 2NaCl (s)
1 mol of chlorine reacts with 2 moles of sodium
Then, 2.3 moles of Cl₂ would react with (2.3 .2) / 1 = 4.6 moles
Let's determine the mass of them.
4.6 mol . 23 g/mol = 105.8 g
