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Lerok [7]
3 years ago
6

What happen when a piece of silver metal is added to the copper sulphate solution​

Chemistry
2 answers:
natta225 [31]3 years ago
7 0

Answer:

Explanation:When silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

patriot [66]3 years ago
6 0

Answer:

There will be no reaction

Explanation:

Therefore, when silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

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A) liquid

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2 years ago
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How many atoms are there in 2.43 g of calcium?
Evgen [1.6K]

Answer:

Explanation:

We're asked to calculate the number of atoms of

Ca

in

153

g Ca

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What we must first do is convert the given mass of calcium to moles of calcium, using its molar mass (referring to a periodic table, this is

40.08

g

mol

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153

g Ca

(

1

mol Ca

40.08

g Ca

)

=

3.82

mol Ca

Using Avogadro's number,

6.022

×

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23

particles

mol

, we can calculate the number of atoms present:

3.82

mol Ca

(

6.022

×

10

23

atoms Ca

1

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=

2.30

×

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24

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3 0
2 years ago
Potassium is isotopic and has RAM of 39.5 work out the percentage abundance of each isotope in a given sample of potassium which
Troyanec [42]

Yo sup??

Let the percentage of K-39 be x

then the percentage of K-40 is 100-(x+0.01)

We know that the net weight should be 39.5. Therefore we can say

(39*x+40*(100-(x+0.01))+38*0.01)/100=39.5  

(since we are taking it in percent)

39*x+40*(100-(x+0.01))+38*0.01=3950

39x+4000-40x-0.4+0.38=3950

2x=49.98

x=24.99

=25 (approx)

Therefore K-39 is 25% in nature and K-40 is 75% in nature.

Hope this helps.

3 0
3 years ago
The limiting reactant, O2, can form up to 2.7 mol Al2O3. What mass of Al2O3 forms?
Margaret [11]

Answer:

280 g Al₂O₃

Explanation:

To find the mass, you need to multiply the given value by the molar mass. This will cause the conversion because the molar mass exists as a ratio; technically, the ratio states that there are 101.96 grams per every 1 mole Al₂O₃. It is important to arrange the ratio in a way that allows for the cancellation of units. In this case, the desired unit (grams) should be in the numerator. The final answer should have 2 sig figs to reflect the given value (2.7 mol).

Molar Mass (Al₂O₃): 101.96 g/mol

2.7 moles Al₂O₃          101.96 g
------------------------  x  -------------------  = 275 g Al₂O₃  = 280 g Al₂O₃
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5 0
2 years ago
I need help with electron affinity chemistry problem. I’m having a tough time.
ExtremeBDS [4]

Answer:

Br Be Ge

Explanation:

Increases in electron affinity

5 0
3 years ago
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