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Lerok [7]
3 years ago
6

What happen when a piece of silver metal is added to the copper sulphate solution​

Chemistry
2 answers:
natta225 [31]3 years ago
7 0

Answer:

Explanation:When silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

patriot [66]3 years ago
6 0

Answer:

There will be no reaction

Explanation:

Therefore, when silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

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The melting point of your product is 10 degrees lower than the expected one. What conclusion can you make about the purity of yo
DanielleElmas [232]

Answer:

The product is significantly impure

Explanation:

In order to test for the purity of a specific sample that was synthesized, the melting point of a compound is measured. Basically speaking, the melting point identifies how pure a compound is. There are several cases that are worth noting:

  • if the measured melting point is significantly lower than theoretical, e. g., lower by 3 or more degrees, we conclude that our compound contains a substantial amount of impurities;
  • wide range in the melting point indicates impurities, unless it agrees with the theoretical range.

Since our compound is even 10 degrees Celsius lower than expected, it indicates that the compound is significantly impure.

5 0
3 years ago
Copper(II) sulfate forms a bright blue hydrate with the formula CuSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high eno
Arada [10]

Answer:

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

Explanation:

CuSO_4.nH_2O\rightarrow CuSO_4+nH_2O

Mass of hydrate of copper sulfate = 14.220 g

Moles of hydrate of copper sulfate =\frac{14.220 g}{(159.5+n\times 18) g/mol}

Mass of copper sulfate after heating = 8.9935 g

Moles of copper sulfate = \frac{8.9935 g}{159.5 g/mol}

\frac{14.220 g}{(159.5+n\times 18) g/mol}=\frac{8.9935 g}{159.5 g/mol}

Solving for n, we get:

n = 5

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

5 0
3 years ago
What is the pH of a 1.9 M solution of HClO4?
Sliva [168]
The compound HClO4, when placed in water, will dissociate into the ions, H+ and ClO4-. Therefore, the 2.0 M solution will also form 2.0 M H+. The pH is calculated through the equation,
pH = -log[H+]
Substituting,
pH = -log[2] = -0.3
Thus, the pH of the solution is -0.3.
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What is the experiment

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3 years ago
Describe all the relationships between pressure, volume, and<br> temperature
hammer [34]
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  • <u> The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).</u>
3 0
3 years ago
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