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3 years ago

In triangle ABC, a = 4, b = 6, and cos C = − 1/4. What is the length of side c?

Mathematics

1 answer:

shusha [124]3 years ago

7 0

The length of side c would be 8.

Step-by-step explanation:

Given that,

a = 4

b = 6

cosC = -1/4

If we are given two sides and angle, the law of Cosines can be used to find the third side:

$c^{2} = a^{2} + b^{2} - 2ab (cos(c))$

By inserting the values in the formula, we get

$c^{2} = 4^{2} + 6^{2} - 2.4.6 (-\frac{1}{4} )$

$c^{2} = 16 + 36 + 12$

$c^{2} = 64$

$\sqrt{c^{2} } = \sqrt{64}$

c = 8.

Therefore, the length of side c would be 8.

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ANSWER
$0.073 \% = 0.00073$

EXPLANATION

Recall that,

$\% = \frac{1}{100}$

That is why
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This implies that,

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This is the same as,

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When we are dividing by
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$0.073\% = 0.00073$

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Step-by-step explanation:

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For this figure what is the value of X?<br><br> How did you solve this?

Ivanshal [37]

Answer:

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Step-by-step explanation:

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