Binomial distribution formula: P(x) = (n k) p^k * (1 - p)^n - k
a) Probability that four parts are defective = 0.01374
P(4 defective) = (25 4) (0.04)^4 * (0.96)^21
P(4 defective) = 0.01374
b) Probability that at least one part is defective = 0.6396
Find the probability that 0 parts are defective and subtract that probability from 1.
P(0 defective) = (25 0) (0.04)^0 * (0.96)^25
P(0 defective) = 0.3604
1 - 0.3604 = 0.6396
c) Probability that 25 parts are defective = approximately 0
P(25 defective) = (25 25) (0.04)^25 * (0.96)^0
P(25 defective) = approximately 0
d) Probability that at most 1 part is defective = 0.7358
Find the probability that 0 and 1 parts are defective and add them together.
P(0 defective) = 0.3604 (from above)
P(1 defective) = (25 1) (0.04)^1 * (0.96)^24
P(1 defective) = 0.3754
P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358
e) Mean = 1 | Standard Deviation = 0.9798
mean = n * p
mean = 25 * 0.04 = 1
stdev =
stdev = = 0.9798
Hope this helps!! :)
Z = 140
X = 40
Y = 40
Explanation:
Z and the angle given (140 degrees) are vertical angles, and are therefore congruent
We know that x and y are vertical angles, so they are also congruent to each other
You know that together, the angles have to add up to 360
140 + 140 + x + y = 360
Another way of putting it:
360-280 = 80
Now, we have to divide by two since we need to find x AND y
80/2 = 40
Therefore, your answers for x and y are 40
To double check, you can add up the angles and see if they equal 360
140 + 140 + 40 + 40
280 + 80 = 360
Answer:
76 degrees
Step-by-step explanation:
find angle 5 by subtracting 76 from 180 to get 104 degrees
the find angle 7 by subtracting 104 from 180 to get 76
180-76 =104
180-104=76
Answer:
<h3><u>Option 1</u></h3>
Earn $50 every month.
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000
This is a <u>linear function</u>.
<h3><u>Option 2</u></h3>
Earn 3% interest each month.
(Assuming the interest earned each month is <u>compounding interest</u>.)
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000
This is an <u>exponential function</u>.
<h3><u>Table of values</u></h3>
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From the table of values, it appears that <u>Account Option 1</u> is the best choice, as the accumulative growth of this account is higher than the other account option.
However, there will be a point in time when Account Option 2 starts accruing more than Account Option 2 each month. To find this, graph the two functions and find the <u>point of intersection</u>.
From the attached graph, Account Option 1 accrues more until month 32. From month 33, Account Option 2 accrues more in the account.
<h3><u>Conclusion</u></h3>
If the money is going to be invested for less than 33 months then Account Option 1 is the better choice. However, if the money is going to be invested for 33 months or more, then Account Option 2 is the better choice.
The answers should be:
A) 6n-4
B) -4n+25