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irga5000 [103]
4 years ago
7

Is 11/2 and 6/11 equivalent? Plz I need the help☹️

Mathematics
1 answer:
trapecia [35]4 years ago
5 0

For this case we have the following fractions:

\frac {11} {2}\\\frac {6} {11}

We must rewrite the fractions, using the same denominator.

We have then:

We multiply the first fraction by 11 in the numerator and denominator:

\frac {11} {2} \frac {11} {11}

We multiply the second fraction by 2 in the numerator and denominator:

\frac {6} {11} \frac {2} {2}

Rewriting we have:

For the first fraction:

\frac {121} {22}

For the second fraction:

\frac {12} {22}

We note that:

\frac {121} {22}> \frac {12} {22}

Answer:

The fractions are not equivalent:

\frac {11} {2}> \frac {6} {11}

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If the base of a parallelogram is 61 m and the area is 645 m2, what is the height of the parallelogram
Sonja [21]

Answer:

645/61

or

10 35/61

or

10.5737704918

Step-by-step explanation:

Area of a parallelogram is base × height

A=b×h

In this situation we know base and area.

645=61×h

To solve for height divide both sides by 61. (dividng area by base)

h=645/61

645/61 = 10 35/61 = 10.5737704918

7 0
3 years ago
Prove the identity (sina-cosatanb)/(cosa+sinatanb) = tan (a+b)
OLga [1]
Sina - (cosa)(tanb)/cosa + (sina)(tanb)
sina ≡ (tana)(cosa)

(tana)(cosa) - (cosa)(tanb)/cosa + (tana)(cosa)(tanb)
= cosa(tana - tanb)/cosa(1 + tanatanb)
(cosas cancel out)
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7 0
3 years ago
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VMariaS [17]

Answer:

LOL

Step-by-step explanation:

5 0
3 years ago
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Find the volume of the prism.
harina [27]
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3 years ago
In 5 years, Dad will be three times as old as his daughter Jill will be then. If the sum of their present ages is 50, how old ar
Nataliya [291]
The answer is <span>b.3x + 15 = 55 - x
</span>
x - Jill's present age
y - dad's present age

<span>In 5 years, Dad will be three times as old as his daughter Jill will be then:
y + 5 = 3(x + 5)

</span><span>The sum of their present ages is 50:
x + y = 50

We have the system of two equations now:
</span>y + 5 = 3(x + 5)
x + y = 50

Let's rearrange the second equation:
If:         x + y = 50     
Then:  y = 50 - x

Now, substitute y from the second equation (y = 50 - x) into the first one:
y + 5 = 3(x + 5)
50 - x + 5 = 3(x + 5)
50 + 5 - x = 3*x + 3*5
55 - x = 3x + 15

Rearrange it a bit:
3x + 15 = 55 - x
Therefore, the correct choice is b.
5 0
3 years ago
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