Answer:
Initial Velocity = 0 m/s
Final Velocity = 34.6 m/s
time = 3.5 s
Explanation:
The initial velocity must be zero since, the egg must be at rest initially, before dropping.
<u>Initial Velocity = 0 m/s</u>
Now, for time we use 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = Height = 61 m
Vi = Initial Velocity = 0 m/s
g = 9.8 m/s²
t =time = ?
Therefore,
61 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t² = (61 m)(2)/(9.8 m/s²)
t = √(12.45 s²)
<u>t = 3.5 s</u>
Now, for final velocity we will use 1st equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(3.5 s)
Vf = 34.6 m/s
Answer:
t=240s
Explanation:
Distance=120m
Acceleration=-5m/s^2
v=0
Let u=x m/s
Using equation v^2-u^2=2as:-
0-x=2(-5)(120)
-x=-1200
x=1200m/s
Using now equation v=u+at:-
0=1200+-5t
5t=1200
t=240s
Answer:
Explanation:
The question relates to Doppler effect and beat.
The observer is moving towards the reflected sound so apparent frequency will be increased
f = f₀ x (V + v₁) / (V - v₂)
f is apparent frequency , f₀ is real frequency , V is velocity of sound , v₁ is velocity of observer and v₂ is velocity of source . Here
v₁ = v₂ = vp as both observer and source have same velocity
f = f₀ x (V + v₁) / (V - v₂)
205 +5 = 205 x (344 +vp)/ ( 344 - vp)
1.0234 = (344 +vp)/ ( 344 - vp)
= 352 - 1.0234vp = 340+vp
12 / 2.0234vp
vp = 6 m /s approx.