Answer:
= 5.1 W
Explanation:
time (t) = 30 ms = 0.03 s
mass (m) = 560 g = 0.56 kg
initial velocity (U) = 0 m/s
final velocity (V) = 0.74 m/s
power = \frac{work done}{t} = \frac{f x d}{t} = f x v = m x a x v
m x a x v = m x \frac{V-U}{t} x \frac{V + U}{2}
m x \frac{V-U}{t} x \frac{V + U}{2} = 0.56 x \frac{0.74 - 0}{0.03} x \frac{0.74+0}{2}
= 5.1 W
Answer:
4. A 10-kilogram sled at rest
Explanation:
The object with most inertia is a 10-kilogram sled at rest.
Inertia is the tendency of a body to remain at rest or continue with uniform motion.
Now, this is better highlighted by Newton's first law of motion which states that "an object will remain in a state of rest or of uniform motion unless it is acted upon by an external force".
- The more the mass of a body, the greater its inertia
- So, the choice with the most mass will have the highest inertia and will be the most reluctant to change position.
<span>The answer for this statement would be true. A person should accept the reality. Never do something that can possibly hurt you in the future. Do not try to do the impossible because at another period, you can may still be able to change the situation. </span>
1)
Answer: A inclined plane and staircase reaching the same height. Work depends on initial and final position only.
Explanation:
The amount of work done does not depend on path length. It depends on initial and final position. It is given by gravitational potential energy.
W = m g h
Where, m is the mass of the object, g is the acceleration due to gravity and h is the height.
Let the mass of the object be m. Two different paths ( one inclines plane and another staircase) are taken to same point. The object would gain same gravitational potential energy because it depends on the height through which the object is taken and not the actual path length.
W ∝ h.
2)
Spring constant can be defined as the ratio of amount of force acting spring with the displacement caused due to the force. A deformed elastic object has elastic potential energy stored in it which is equal to the work done to deform the object. It is proportional to the spring constant and amount of stretched distance.
Equilibrium is reached when the net force acting on the spring is zero. In equilibrium state, the object has natural extension. An object is said to possess elastic potential energy when force is applied and object deforms relative to original equilibrium shape or length.
Answer:
Stated below:
Explanation:
Let's calculate the maximum height
.
H=v^2/2g=320mH=v
2
/2g=320m
PE=mgh=0.1*10*320=320 J
at halfway up PE will be half of max = 320/2=160 J
KE will be equal to PEmax=320 J.
Hope I helped! ☺
