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3 years ago

Need Help on this, First RIGHT answer gets brainliest :)

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

The answer is 50% as half the circle is shaded!

torisob [31]3 years ago

6 0

Answer:

50%

Step-by-step explanation:

The circle is split into 4 parts and there are 2 parts of the circle shaded.

Step 1:

2/4 = 50/100

Step 2:

50/100 = 50%

Answer:

50%

Hope This Helps :)

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Answer:

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Ugo [173]

Answer:

$y=-3.2\\\\y=-2.2\\\\y=-1.8$

Step-by-step explanation:

Insert the given x values for the given equation to find the corresponding y coordinate:

$y=0.2x-2$

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$y=0.2(-6)-2$

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$y=-3.2$

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Insert 1:

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2 years ago

5. Find the general solution to y'''-y''+4y'-4y = 0

CaHeK987 [17]

For any equation,

$a_ny^(n)+\dots+a_1y'+a_0y=0$

assume solution of a form, $e^{yt}$

Which leads to,

$(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0$

Simplify to,

$e^{yt}(y^3-y^2+4y-4)=0$

Then find solutions,

$\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}$

For non repeated real root y, we have a form of,

$y_1=c_1e^t$

Following up,

For two non repeated complex roots $y_2\neq y_3$ where,

$y_2=a+bi$

and,

$y_3=a-bi$

the general solution has a form of,

$y=e^{at}(c_2\cos(bt)+c_3\sin(bt))$

Or in this case,

$y=e^0(c_2\cos(2t)+c_3\sin(2t))$

Now we just refine and get,

$\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}$

Hope this helps.

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3 years ago

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Ludmilka [50]

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