An Expression is shown below. - 5 12 + 7 34 What is the value of the Expression?

On one day a Plumber Joe earned $80 on a plumbing job. Out of his earnings he spent $6.85 on tea and snacks, $5.50 on food and $

In-s [12.5K]

Answer:

Joe saved 68.25

Step-by-step explanation:

Subtract 6.85 from 80, you get 73.15

Subtract 5.50 from 73.15 and you get 67.65.

Subtract 21.40 from 67.65 and you get 46.25.

Add 22 to that amount, you get 68.25.

P.S

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4 0

2 years ago

In the Jefferson Middle School chorus, 60% of the members are girls. If there are 45 girls in chorus what is the total number of

PtichkaEL [24]

There are 75 chorus members.

4 0

3 years ago

In a large population, 82% of the households have cable tv. A simple random sample of 225 households is to be contacted and the

anzhelika [568]

Answer:

The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, the mean is $\mu = p$ and the standard deviation is $s = \sqrt{\frac{p(1-p)}{n}}$

In this problem, we have that:

$p = 0.82, n = 225$ .

So

$\mu = 0.82$

$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.82*0.18}{225}} = 0.0256$

The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.

7 0

2 years ago

Read 2 more answers

Suppose the claim size of an auto collision insurance, X, is uniformly distributed on the interval $1,000 to $10,000. What is th

timurjin [86]

Answer:

35.35%

Step-by-step explanation:

If there were no deductibles, the expected claim payment would be:

$E(X) = \frac{10,000 +1,000}{2} \\E(X) =\$5,500$

If the collision insurance claim is under $2,000, then the insurer would not pay anything, but if X > $2,000, then the insurer would pay X - $2,000. The new expected value is:

$E_2(X)=\frac{2,000-1,000}{10,000-1,000} *0+\frac{10,000-2,000}{10,000-1,000}*\frac{(2,000-2,000)+(10,000-2,000)}{2} \\E_2(X)=\frac{8}{9}*\frac{0+8,000}{2}\\ E_2(X)=\$3,555.56$

The percentage reduction on the claim payment is:

$P=(1-\frac{E_2(X)}{E(X)})*100 \\P=(1-\frac{3,555.56}{5,500})*100\\P=35.35\%$

There was a 35.35% reduction.

8 0

3 years ago

What is the decay factor in the exponential decay function y=a (1-r) t

MrRissso [65]

Answer:

in this form, the "-r" would cause the result to decrease

I assume that the answer is "r"

if r = .1 (10 %) then 1-.1 = .9

if you have 100 items then y = 100(.9)^1 = 90

the total decreased by 10% ... y = 100(.9)^2 after 2 time periods

Step-by-step explanation:

5 0

2 years ago