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LuckyWell [14K]
3 years ago
14

An Expression is shown below. - 5 12 + 7 34 What is the value of the Expression?

Mathematics
1 answer:
fgiga [73]3 years ago
4 0

Answer:

Step-by-step explanation:

IDK

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Find the excluded value of the function Y= - 10/6x-5. The excluded value is x =??
Masteriza [31]

Answer:

The excluded value is x = 5/6

Step-by-step explanation:

Here, we want to calculate the excluded value

The excluded value is simply the value of x that will make the denominator of the fraction equals zero

We have this as;

6x -5 = 0

6x = 5

x = 5/6

8 0
3 years ago
I need to solve this.
Svetradugi [14.3K]

Answer:

3

3

5

2

Step-by-step explanation:

What kind of math is this and what grade are you in?

5 0
3 years ago
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The diameter and height of this cylinder are equal to the side length ,S, of the crude in which the cylinder is inscribed.What e
yulyashka [42]

Answer:

c

Step-by-step explanation:

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3 0
3 years ago
In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t
Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

(Y_1)^2 and (Y_2)^2 have x^2 distribution with 1 degree of freedom

and V=(Y_1^2)+(Y_2)^2 has x^2 with 2 degree of freedom

F_v(v)=\frac{e^{-\frac{v}{2}}}2

Since we have to find the density formula

U=\sqrt{V}

We use method of transformation

h(V)=\sqrt{U}\\\\=U

There inverse function is h^-^1(U)=U^2

We derivate the fuction above with respect to u

\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u

Therefore,

F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U

8 0
3 years ago
What is the classification for this polynomial?6
Fantom [35]

one term is monomial

two terms are binomials

three terms are trinomials

each term is separated by a + or - sign

so......6 has only  one term ......it is a monomial

6 0
3 years ago
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