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3 years ago

15

on the surface of jupiter the acceleration due to gravity is about 3 times that on earth. how much would a 100kg rock weigh on j

upiter?

2 answers:

snow_lady [41]3 years ago

6 0

Answer:

2940 N

Explanation:

Given at Jupiter acceleration due to gravity( $g_j$ ) is equal to 3 times of acceleration due to gravity on the Earth( $g_e$ ).

That is,

$g_j=3g_e$

We know, $g_e=9.8m/s^2$

So, $g_j=3\times9.8=29.4m/s^2$

Now the gravitational force on Jupiter (weight on Jupiter) is given as

$W = mg_j$

Here m = 100 kg is the mass and it remain same on both earth and Jupiter.

Substitute the given values, we get

$W=100 kg\times 29.4m/s^2$

W = 2940 N.

Thus, the weight of 100 kg rock on the Jupiter is 2940 N.

madam [21]3 years ago

4 0

Answer:

Weight on Jupiter will be equal to 2940 N

Explanation:

We have given given acceleration due to gravity on Jupiter is 3 times of acceleration due to gravity on earth

Acceleration due to gravity on earth $g=9.8m/sec^2$

So acceleration due to gravity on Jupiter = $g'=3\times 9.8=29.4m/sec^2$

Mass is given m = 100 kg

We have to find the weight

Weight is equal to W = mg, here m is mass and a is acceleration

So weight $W=100\times 29.4=2940N$

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3 years ago

the force between a planet and a spacecraft is 1 million newtons. whst will the force be iv the spacecraft moves to halfg its or

dybincka [34]

The forces of gravity between two objects are inversely proportional to
the square of the distance between them. So reducing the distance
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The 1 million newtons becomes 4 million newtons.

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When you're calculating gravitational forces, it's the distance between
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3 years ago

An insulated rigid tank initially contains 1.4-kg saturated liquid water and water vapor at 200°C. At this state, 25 percent of

Elan Coil [88]

Solution:

Mass of liquid water and water vapor in the insulated tank initially = 1.4 kg

Temperature = 200 °C

And 25% of the volume by liquid water is steam.

State 1

$m=\frac{V}{v}$

$m=m_f+m_g$

$1.4=\frac{0.25V}{v_f}+\frac{0.75V}{v_g}$

$1.4=\frac{0.25V}{1.1565 \times 10^{-3}}+\frac{0.75V}{0.1274}$ (taking the value of $v_g$ and $v_g$ at 200°C )

$V=6.304 \times 10^{-3}$

Now quality of vapor

$x=\frac{m_g}{m}$

$=3.377 \times 10^{-3}$

Internal energy at state 1 can be found out by

$u_1=u_f+xu_{fg}$

$=850.65+3.377\times10^{-3}\times 1744.65$

= 856.54 kJ/kg

After heating with the resistor for 20 minutes, at state 2, the tank contains saturated water vapor $v_2=v_g \text { and }\ x=1$

Tank is rigid, so volume of tank is constant.

$v_g=v_2=\frac{V}{m}$

$v_g=\frac{6.304\times 10^{-3}}{1.4}$

$v_g=4.502 \times 10^{-3} \ m^3 /kg$

Now interpolate the value to get temperature at state 2 with specific volume value to get final temperature

$T_2=360+(374.14-360)\left(\frac{0.004502-0.006945}{0.003155-0.006945}\right)$

= 369.11° C

Internal energy at state 2

$u_2=2154.9 \ kJ/kg$

Now power rating of the resistor

$P=\frac{m(u_2-u_1)}{t}$

$P=\frac{1.4(2154.9-856.54)}{20 \times 60}$

= 1.51 kW

6 0

3 years ago

The purpose of the defense is to _____.

BigorU [14]

Hello,

The purpose of the defense is to <span>prevent the opposing offense from advancing the ball.

Explanation: Defense is to defend our team or group so that the other team or group does not win or take the ball from us or even advance the ball.

Hope this helped!

~HotTwizzlers</span>

7 0

3 years ago

Read 2 more answers

If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforc

Allisa [31]

Answer:

the net force applied to the car is zero.

Explanation:

According to Newton's second law, the acceleration of an object (a) is directly proportional to the net force applied (F):

$a=\frac{F}{m}$

where m is the object's mass.

In this problem, the car is moving with constant velocity: this means that the acceleration is zero, a = 0. Therefore, according to the previous equation, the net force must also be zero: F = 0. So, the correct answer is

the net force applied to the car is zero.

3 0

3 years ago