Answer:
Explanation:
A mass of 700 kg will exert a force of
700 x 9.8
= 6860 N.
Amount of compression x = 4 cm
= 4 x 10⁻² m
Force constant K = force of compression / compression
= 6860 / 4 x 10⁻²
= 1715 x 10² Nm⁻¹.
Let us take compression of r at any moment
Restoring force by spring
= k r
Force required to compress = kr
Let it is compressed by small length dr during which force will remain constant.
Work done
dW = Force x displacement
= -kr -dr
= kr dr
Work done to compress by length d
for it r ranges from 0 to -d
Integrating on both sides
W = 
= [ kr²/2]₀^-4
= 1/2 kX16X10⁻⁴
= .5 x 1715 x 10² x 16 x 10⁻⁴
= 137.20 J
Answer:
D.)it orbits near the Kepler belt
Explanation:
The Kuiper belt is an area similar to the asteroide belt extending from the orbit of Neptune to about 50 AU from the Sun. It mainly consists of icy asteroids and dwarf planets, which are rocky objects big enough to be defined as planet but that do not have enough gravity to clear their orbit from other obejcts.
Pluto was discovered in 1930 - initially it was classified as a planet, although it is much smaller than the other 8 planets of the Solar System. However, it has been recently de-classified to dwarf planet because its gravity is not enough to clear its orbit from other objects (asteroids). Pluto is located inside the Kuiper belt, so option D is correct. Other dwarf planets in the Kuiper belt are for instance Haumea and Makemake.
Answer:
a. 900 J
b. 0.383
Explanation:
According to the question, the given data is as follows
Horizontal force = 150 N
Packing crate = 40.0 kg
Distance = 6.00 m
Based on the above information
a. The work done by the 150-N force is


= 900 J
b. Now the coefficient of kinetic friction between the crate and surface is


= .383
We simply applied the above formulas so that each one part could calculate
Answer:
The value of the acceleration of gravity of the Unknown Planet = 1.14 
Explanation:
length of the pendulum (L)= 1.15 m
Time period (T)= 6.29 seconds
We know that time period of a simple pendulum is given by
⇒ T = 2
×
put the values in the above formula we get
⇒ T = 2
× 
⇒ 6.29 = 2
× 
By solving the above equation we get
⇒ g = 1.14 
This is the value of the acceleration of gravity of the Unknown Planet.
Do you mean mitosis? If so metaphase.