the gravitational force acts on all objects in proportion to their mass. neglecting air resistance, why don’t heavy objects fall
1 answer:
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Answer:
Option B
Explanation:
Given information
Radius of container, r=12cm=12/100=0.12m
Angular velocity= 2 rev/s, converted to rad/s we multiply by 2π
Angular velocity,
We know that speed,
Centripetal acceleration, and substituting
we obtain that
Substituting \omega for 12.56637061 and r for 0.12
Rounded off,
I attached a Diagram for this problem.
We star considering the system is in equlibrium, so
Fm makes with vertical
Fm makes 70 with vertical
Applying summatory in X we have,
We know that W is equal to
Substituting,
<em>For the second part we know that the reaction force Fj on deltoid Muscle is equal to Fm, We can assume also that</em>
The charge of the object must be
Answer: Option C
<u>Explanation:</u>
Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.
Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.
Here, given E = 4500 N/C and F = 0.05 N.
We need to find charge of the object (q)
By substituting the given values, we get
