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vovikov84 [41]
3 years ago
10

The purpose of the defense is to _____.

Physics
2 answers:
BigorU [14]3 years ago
7 0
Hello,

The purpose of the defense is to <span>prevent the opposing offense from advancing the ball.

Explanation: Defense is to defend our team or group so that the other team or group does not win or take the ball from us or even advance the ball.

Hope this helped!

~HotTwizzlers</span>
zheka24 [161]3 years ago
3 0
"<span>prevent the opposing offense from advancing the ball"  Is the answer you are looking for, this is because the defense is to protect or prevent.

Hope this helps!</span>
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A closed system consists of 0.3 kmol of octane occupying a volume of 5 m3 . Determine
Alenkinab [10]

Answer:

(a). The weight of the system is 336.32 N.

(b).  The molar volume is 16.6 m³/k mol.

The mass based volume is 0.145 m³/kg.

Explanation:

Given that,

Weight of octane = 0.3 kmol

Volume = 5 m³

(a). Molecular mass of octane

M=114.28\ g/mol

We need to calculate the mass of octane

Mass of 0.3 k mol of octane is

M=114.28\times0.3\times1000

M=34.284\ kg

We need to calculate the weight of the system

Using formula of weight

W=mg

Put the value into the formula

W=34.284\times9.81

W=336.32\ N

(b). We need to calculate the molar volume

Using formula of molar volume

\text{molar volume}=\dfrac{volume}{volume of moles}

Put the value into the formula

\text{molar volume}=\dfrac{5}{0.3}

\text{molar volume}=16.6\ m^3/k mol

We need to calculate the mass based volume

Using formula of mass based volume

\text{mass based volume}=\dfrac{volume}{mass}

Put the value into the formula

\text{mass based volume}=\dfrac{5}{34.284}

\text{mass based volume}=0.145\ m^3/kg

Hence, (a). The weight of the system is 336.32 N.

(b).  The molar volume is 16.6 m³/k mol.

The mass based volume is 0.145 m³/kg.

3 0
3 years ago
Frank and Lisa are analyzing the chart, which shows the speed at which light travels through different media. Frank says that li
Lelechka [254]
The correct answer is
c) Neither person is correct because light does not change frequency when it travels through different media

In fact, light changes both wavelength and speed when it travels through different media, but the frequency remains the same.
4 0
3 years ago
Read 2 more answers
A.
lorasvet [3.4K]

Answer:

A) Option 1 is the correct answer.

B) Option 4 is the correct answer.

Explanation:

A) Weight of liquid = 7 N

    Volume of liquid = 1 L = 0.001 m³

    Specific weight =  \frac{7}{0.001}=7000N/m^3

    Density = \frac{7000}{9.81}=713.5kg/m^3

    Specific gravity = \frac{713.5}{1000}=0.7135

    Option 1 is the correct answer.

B) The Stokes(St) is the cgs physical unit for kinematic viscosity, named after George Gabriel Stokes.

We have

             1 St = 10⁻⁴ m²/s

    Option 4 is the correct answer.        

7 0
3 years ago
Sandy is on a road trip. She leaves at 8:00 AM. It takes her 2 hours to drive 200 kilometers. She stops at a rest stop for half
lutik1710 [3]
The average velocity of Sandy is given by the total distance covered S divided by the total time taken t:
v= \frac{S}{t}

The total distance covered is
S=200 km+0+100 km=300 km
while the total time taken is 2 hours + half an hour (for the rest) + 1 hour and half, so
t=2h+0.5h+1.5 h=4 h
Therefore, the average velocity is 
v= \frac{S}{t}= \frac{300 km}{4 h}=75 km/h
0 0
3 years ago
The Pacific Plate is moving 29 mm/year toward the north and 20 mm/year toward the west relative to the North American Plate. Sho
adell [148]

Answer:

7 mm per year

Explanation:

It is given that :

The Pacific plate is moving towards north at = 29 mm per year

The Pacific plate is moving towards west at = 20 mm per year

We have to calculate the total relative motion towards the northwest.

So we have to find the resultant of the two motions.

Since the two movements are perpendicular, therefore the angle between the two motions is 90 degree.

Therefore, finding their resultant,

R^2=(29)^2+(20)^2

R^2=(49)^2

R = 7

Therefore, total relative motion towards the northwest is 7 mm per year.

   

4 0
3 years ago
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