"Constant velocity" means zero acceleration, which means zero net force. So there must be100N pulling on the crate to cancel the 100N of friction force.
Hello. You did not enter the data to which this question refers, which makes it impossible for it to have an exact answer. However, I will try to help you in the best possible way.
The forces that hold the elements together are called intermolecular forces. They are formed by covalent bonds between the molecules and can be called: dipole-induced (occurs between nonpolar molecules that have a negative pole and a positive pole) and dipole-dipole (occurs between polar moileculas, except when hydrogen is present).
Ionic solutes are considered strong electrolytes. What does this mean for the conductivity of the solution?
A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.
B) Strong electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.
C) Being a strong electrolyte refers the type of bonding and has no bearing on conducting electricity.
D) Strong electrolytes do not dissolve in water and can not conduct electricity.
ANSWER:
A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.
Answer:
318.5 x 10^4 Pa
Explanation:
weight of woman = m g = 65 x 9.8 = 637 N
Area of both the heels = 1 x 2 = 2 cm^2 = 2 x 10^-4 m^2
Pressure is defined as the thrust acting per unit area.
P = F / A
Where, F is the weight of the woman and A be the area of heels
P = 637 / (2 x 10^-4) = 318.5 x 10^4 Pa
Answer:
1.55 m
Explanation:
The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:
As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.
Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:
The distance between both points, is just the difference between the radius of both spheres, as follows:
r₂ - r₁ = 1.55 m
